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Yuri [45]
3 years ago
6

Which law states that the volume and absolute temperature of a fixed quantity of gas are directly proportional under constant pr

essure conditions?
Boyle’s law
Charles’s law
Dalton’s law
Gay-Lussac’s law
Chemistry
2 answers:
Delvig [45]3 years ago
8 0
<h2>Hello!</h2>

The answer is: Charle's Law.

<h2>Why?</h2>

The law that states that the volume and absolute temperature of a fixed quantity of gas (ideal gas) are proportional under constant pressure is the Charle's Law, also known as the law of volumes.

The law describes how a gas kept under constant pressure tends to expand when the temperature increases and it's described by the following equation:

\frac{V}{T}=k

Where,

V=Volume\\T=Temperature\\k=constant

Also, to describe the relationship between two differents volumes at different temperatures, we have:

\frac{V_{i}}{T_{i}}=\frac{V_{f}}{T_{f}}

Where,

V_{i}=InitialVolume\\T_{i}=InitialTemperature\\V_{f}=FinalVolume\\T_{f}=FinalTemperature

Have a nice day!

Ivenika [448]3 years ago
7 0

Answer:

On Ed it is Gay-Lussac’s law

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When the pH decreases from 6 to 3, the hydrogen ion, H+, increases by what?
Irina-Kira [14]

pH decreases as the hydrogen ion concentration increases.

<u>Explanation:</u>

When there is a decrease in pH, that is pH decreases from 6 to 3 then the acidity increases.

That is the pH is between 1 to 7 then it is acidic

When the pH is 7 then it is neutral

When the pH is between  7 to 14 then it is basic

As the H⁺ ion concentration increases, then the pH value decreases, here pH decreases from 6 to 3.

So the concentration of Hydrogen ion increases, pH decreases.

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3 years ago
Can someone help? I wasn't at school the day we did this and I don't understand.
Anton [14]
1) 2700 kg/l
2) 13.6 kg/l
3) 0.1578 kg
4) 8921.5 kg/m3
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Just divide the masses by volume to find out the density, multiply the volume with density to find out the mass and divide the mass by density to find out the volume.
To turn the result into SI unit (kg/l), divide the g by 1000 and ml by 1000.
7 0
3 years ago
Do guitar strings deform? and how??
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5 0
3 years ago
A student used 1.168g of an unknown weak acid and titrated it against 28.75 mL of 0.105M NaOH to reach the equivalence point. Wh
Vaselesa [24]

Answer:

The molar mass of the unknown acid is 386.8 g/mol

Explanation:

Step 1: Data given

Mass of the weak acid = 1.168 grams

volume of NaOH = 28.75 mL = 0.02875 L

Molarity of NaOH = 0.105 M

Since we only know 1 equivalence point, we suppose the acid is monoprotic

Step 2: Calculate moles NaOH

Moles NaOH = molarity NaOH * volume NaOH

Moles NaOH = 0.105 M * 0.02875 L

Moles NaOH = 0.00302 moles

We need 0.00302 moles of weak acid to neutralize the NaOH

Step 3: Calculate molar mass of weak acid

Molar mass = mass / moles

Molar mass = 1.168 grams / 0.00302 moles

Molar mass = 386.8 g/mol

The molar mass of the unknown acid is 386.8 g/mol

3 0
3 years ago
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