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jonny [76]
3 years ago
14

What is crystal field splitting?

Chemistry
1 answer:
kvv77 [185]3 years ago
4 0

Answer:

Crystal field splitting is the difference in energy between d orbitals of ligands. Crystal field splitting number is denoted by the capital Greek letter Δ. Crystal field splitting explains the difference in color between two similar metal-ligand complexes.

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Radioactive elements decay via first-order kinetics. consider a certain type of nucleus that has a rate constant of 2.4 × 10–2 h
Leokris [45]

Answer:

37.15 h.

Explanation:

  • The decay of radioactive elements obeys first-order kinetics.
  • For first-order reaction: <em>kt = lna/(a-x).</em>

where, k is the rate constant of the reaction <em>(k = 2.4 x 10⁻² h⁻¹)</em>.

t is the time of the reaction <em>(t = ??? day)</em>.

a is the initial concentration of nuclides <em>(a = 100 %)</em>.

(a-x) is the remaining concentration of nuclides <em>(a - x = 100% - 59% = 41.0 %)</em>.

<em>∴ kt = lna/(a-x)</em>

(2.4 x 10⁻² h⁻¹)(t) = ln(100.0%)/(41.0%).

(2.4 x 10⁻² h⁻¹)(t) = 0.8916.

<em>∴ t </em>= (0.8916)/(2.4 x 10⁻² h⁻¹) = <em>37.15 h.</em>

6 0
3 years ago
Compare the type of change that occurs when a substance melts and when a substance is set on fire. Use complete sentences to jus
Amiraneli [1.4K]

When a substance melts it has changed from a solid to a liquid state while when a substance is set on fire is changes from liquid to gaseous state as it boils.

<h3>What is change of state?</h3>

Change of state of matter is the transformation of a substance from one phase of matter to another.

When a substance melts it has changed from a solid to a liquid state while when a substance is set on fire is changes from liquid to gaseous state as it boils.

Learn more about matter here:

brainly.com/question/3998772

#SPJ1

8 0
2 years ago
Read 2 more answers
What is the energy of an electromagnetic wave with a frequency of 3 x 109
vladimir2022 [97]

Answer:A

Explanation:

6 0
3 years ago
Read 2 more answers
(A) H2SeO4(aq) + 2 Cl-(aq) + 2 H+(aq) → H2SeO3(aq) + Cl2(g) + H2O(l) (B) S8(s) + 8 O2(g) → 8 SO2(g) (C) 3 Br2(aq) + 6 OH-(aq) →
AVprozaik [17]

Answer:

C)

Explanation:

Oxidation occurs when the Nox number increases and a reduction occurs when the Nox number decreases. So, let's verify in which reaction the same reactant has elements that both occur after the reaction.

A) H₂SeO₄: H = +1, O = -2 (fixed)

Se: x +2*1 + 4*(-2) = 0

x + 2 - 8= 0

x = +6

Cl⁻: -1 (ions have Nox equal to its charge)

H⁺: +1

H₂SeO₃: H = + 1, O = -2

Se: x +2*1 + 3*(-2) = 0

x + 2 -6 = 0

x = + 4 (Se reduces)

Cl₂: Cl = 0 (simple molecule, so Cl oxides)

H₂O: H = +1, O = -2

B) S₈: S = 0

O₂: O = 0

SO₂: O = -2, S: x + 2*(-2) = 0 -> x = +4 (S oxides and O reduces)

C) Br₂: Br = 0

OH⁻ : O = -2, H = +1

Br⁻ = -1 (Br reduces)

BrO₃⁻: O = -2, Br: x +3x(-2) = -1 -> x = +5 (Br oxides)

H₂O: H = +1, O = -2

D) Ca²⁺: Ca = +2

SO₄²⁻: O = -2, S: x +4*(-2) = -2 -> x = +6

CaSO₄: O = -2, S = +6, Ca = +2

E) PtCl₄: Cl = -1 (fixed), Pt: x + 4*(-1) = 0 -> x = +4

Cl⁻: Cl = -1

PtCl₆²⁻: Cl = -1, Pt = x + 6*(-1) = -2 -> x = +4

So, only in letter C Br₂ is undergoes both oxidation and reduction.

4 0
3 years ago
The following combinations are not allowed. If n and ml are correct, change the l value to create an allowable combination:
Lera25 [3.4K]

The allowable combination for the atomic orbital is n=4, l=2, m_{l}=2.

<h3>What are the three quantum numbers of an atomic orbital?</h3>

Three quantum numbers specify an atomic orbital:

- The principal quantum number, n, which is a positive integer, describes the relative size of the orbital and its distance from the nucleus.

- l is the angular momentum quantum number that is related to the shape of the orbital; l is an integer from 0 to n-1 (so n limits l ),

- $\boldsymbol{m}_{l}$ is the magnetic quantum number that prescribes the three-dimensional shape of the orbital around the nucleus; m_{l} values are integers from -l to =l(l limits ml)

For n = 4, l can four values: 0, 1, 2, and 3. To be consistent with m_{l}=+2the l value must be higher than 1. There are two l values that are consistent with n and m_{l} values:  l= 2 or 3

Therefore, the allowable condition is n=4, l=2, m_{l}=2

To know more about quantum numbers, visit: brainly.com/question/16979660

#SPJ4

3 0
2 years ago
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