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Rudiy27
2 years ago
8

A pet store is having a sale on bone shaped chew toys and bags of bacon flavored treats for dogs magrissima and Martin took adva

ntage of the sale merissa presaged 3 chew toys and 4 bags if treats for $27.60 Martin purchased 2 chew toys and 2 bags kf treats for $16.50 what is the price for 1 bag of treat
Mathematics
1 answer:
Bad White [126]2 years ago
6 0
$2.85 thank you hope this helps
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ANTONII [103]
First, and most important, you must know what the question is. You haven't told us what the question is, and a gray cloud hangs like a dark mist over the problem, giving the unmistakable impression that you're not too sure of it yourself.
7 0
3 years ago
You have botles of water how many can you buy with a 20$ and a bottle is 1.25​
igomit [66]

Answer:

16 bottles

Step-by-step explanation:

you can buy 16 bottles

7 0
3 years ago
Would the hypotenuse of a right triangle with a vertical length of 6 and a horizontal length of 10 have the same slope as the hy
Elodia [21]
No

1. Vertical 6, horizontal 10
6/10 = 3/5 slope

2. (Red) vertical -2, horizontal 3
-2/3 does not equal 3/5

3. (Blue) vertical 4, horizontal 6
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3 0
2 years ago
The current population of a town is 10,000 and its growth in years can be represented by P(t) = 10,000(0.2)^t, where t is the ti
DiKsa [7]

Answer:

1) 20%

2) Choice a.

Step-by-step explanation:

P(t)=10000(0.2)^t

1) P(0) is the population initially.

P(1) is the population after a year.

\frac{P(1)}{P(0)} represents the population increase factor.

So let's evaluate that fraction:

\frac{P(1)}{P(0)}

\frac{10000(0.2)^1}{10000(0.2)^0}

\frac{0.2^1}{0.2^0}=\frac{0.2}{1}=0.2

0.2=20%

2) Let's figure out the population growth in terms of months instead of years.

P(t)=10000(0.2)^{t}

We want t to represent months.

A full year is 12 months, in a full year we have that P(1)=10000(0.2)^1=10000(0.2)=2000

So we want a new P such that P(12)=2000 since 12 months equals a year.

Let's look at the functions given to see which gives us this:

a) P(12)=10000(0.87449)^{12}=2000 \text{approximately}

b) P(12)=10000(0.87449)^{12(12)}=0 \text{ approximately}

c) P(12)=10000(0.87449)^{\frac{1}{12}}=9889 \text{approximately}

d) P(12)=10000(0.87449)^{12+12}=400 \text{approximately}

So a is the function we want.

Also another way to look at this:

P(t)=10000(.2)^t where t is in years.

P(t)=10000(.2^\frac{1}{12})^t where t is in months.

And .2^\frac{1}{12}=0.874485 \text{approximately}

8 0
3 years ago
A sample of size 126 will be drawn from a population with mean 26 and standard deviation 3. Use the TI-84 calculator.
GenaCL600 [577]

Answer:

1. The probability that x will be more than 25 is 0.6305.

2. The 55th percentile is 26.38.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean 26 and standard deviation 3.

This means that \mu = 26, \sigma = 3

1 Find the probability that x will be more than 25.

This is 1 subtracted by the p-value of Z when X = 25. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{25 - 26}{3}

Z = -0.333

Z = -0.333 has a p-value of 0.3695.

1 - 0.3695 = 0.6305.

The probability that x will be more than 25 is 0.6305.

2 Find the 55th percentile of x.

This is X when Z has a p-value of 0.55, so X when Z = 0.125.

Z = \frac{X - \mu}{\sigma}

0.125 = \frac{X - 26}{3}

X - 26 = 0.125*3

Z = 26.38

The 55th percentile is 26.38.

7 0
2 years ago
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