Nitrogen Oxygen Chlorine Argon
It would be covalent bonds
Answer:
ΔrxnHº =-1,124.3 kJ
Explanation:
To solve this question we first need to search for the enthalpies of formation of reactants and products and calculate the change in enthalpy of reaction utilizing the equation
ΔrxnHº = ∑ νΔfHº reactants - Σ νΔfHº products
where ν is the stoichiometric coefficient of the compound in the balanced equation .
ΔfHº H₂S(g) = -20.50 kJmol⁻¹
ΔfHº 0₂(g) = 0 ( O₂ is in standard state )
ΔfHº H₂O(l) = -285.8 kJmol⁻¹
ΔfHº SO₂(g) = -296.84 kJmol⁻¹
ΔrxnHº = [2 x -285.8 + 2 x -296.84] - [2 x -20.50]
= - 1,124.3 kJ
Need to use the formula---> final amount= initial amount x (1/2)^(t/h), where t is time and h is half-life. time between noon and 2 pm is two hours. half life is 1 hour
final amount = 40.0 g x (1/2)^( 2 hours/1 hour)= 10 grams
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