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Ksenya-84 [330]
3 years ago
15

1. Amy's science teacher shows her class a model of an atom. Why is a model useful for studying atoms?

Chemistry
1 answer:
trapecia [35]3 years ago
3 0

Answer:

The parts of an atom cannot be directly observed.

Explanation:

An atom is the smallest indivisible particle of a substance that can take part in a chemical reaction.

Atoms are not observed with naked eyes because they are found in the realm of very small particles. It is impossible to observe the parts of an atom directly.

As a result of this, models suffice in explaining the parts of an atom. Hence the answer.

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2 Mg (s) + CO2 (g)  2 MgO (s) + C (s)
denis-greek [22]

Answer:

0.63g

Explanation:

5 0
3 years ago
Matching
kotegsom [21]

Answer:

a mixture of molecules - Box f

atoms of a pure elementa metal - Box D

a solid compound - Box C

a mixture of elements - Box A

Explanation:

Box a has mixture of elements which forms a solid like shape but there are different elements present in the box. The box f has mixture of molecules in which many atoms are combined together. Box c has solid compound with single element.

5 0
3 years ago
Consider the reaction below. HI + H2O mc014-1.jpg H3O+ + I– Which is an acid-conjugate base pair? HI and H2O H2O and H3O+ H3O+ a
lesya692 [45]

Answer: Option (d) is the correct answer.

Explanation:

According to Bronsted-Lowry, species which donate a proton are known as acid. The species which accept a proton are known as a base.

In the given reaction, acids and bases are as follows.

    HI  +   H_{2}O \rightarrow    H_{3}O^{+}           +         I^{-}

 Acid        Base     Conjugate acid   Conjugate base

Therefore, the acid HI loses a proton to form a conjugate base that is I^{-}.

Thus, we can conclude that HI and I^{-} is an acid conjugate base pair.

4 0
4 years ago
Read 2 more answers
The molar heat of fusion for water is 6.01 kJ/mol. How much energy must be added to a 75.0-g block of ice at 0°C to change it to
andreyandreev [35.5K]
Answer is: 25,06 kJ of energy must be added to a 75 g block of ice.
ΔHfusion(H₂O) = 6,01 kJ/mol.
T(H₂O) = 0°C.
m(H₂O) = 75 g.
n(H₂O) = m(H₂O) ÷ M(H₂O).
n(H₂O) = 75 g ÷ 18 g/mol.
n(H₂O) = 4,17 mol.
Q = ΔHfusion(H₂O) · n(H₂O)
Q = 6,01 kJ/mol · 4,17 mol
Q = 25,06 kJ.
7 0
3 years ago
Read 2 more answers
Blood cells. What two effects will such a condition have on the patient?
Rasek [7]
The patient will have less hemoglobin in the blood

The patient will have a reduced oxygen supply to the cells
6 0
4 years ago
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