Question

If the angles are represented in degrees,find both angles: csc(2x+9) =sec(3x+26) Please respond quick

Answer 1

Answer:

Before solving the given trigonometric relation change everything to sines and cosines

Step-by-step explanation:

consider the given equation;

$1/sin(2x+9)$=$1/cos(3x+26)$

Multiplying the above equation on both sides by $cos(3x+26)sin(2x+9)$ then we get,

$cos(3x+26)=sin(2x+9)$

By using identity,$cos a=sin(90-a)$ expand above equation we will get,

$sin(90-(3x+26))=sin(2x+9)$

Then,

$90-3x+26=2x+9$

$x=11$

So the required value of the angle is $11$ degree.