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Sedbober [7]
3 years ago
6

Let fx) = 8x-3 What is (5)? O A. 40 O B. 37 O C. 45 O D. 43

Mathematics
1 answer:
saveliy_v [14]3 years ago
8 0

Answer:

I'm not sure i think B. 37

Step-by-step explanation:

f(x) = 8x-3

f(5)= 8(5)-3

40-3=37

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Find (r-s) (t-s) + (s-r) (s-t) for all numbers r, s, and t. (a) 0 (b) 2 (c) 2rt (d) 2(s-r) (t-s) (e) 2(r-s) (t-s)
lyudmila [28]
Notice that the 2 expressions have 2 common terms.

(r-s) is just (s-r) times (-1)

similarly

(t-s) is just (s-t) times (-1)

this means that :

(r-s) (t-s) + (s-r) (s-t)=-(s-r)[-(s-t)]+(s-r) (s-t)

the 2 minuses in the first multiplication cancel each other so we have:

-(s-r)[-(s-t)]+(s-r) (s-t)=(s-r) (s-t)+(s-r) (s-t)=2(s-r) (s-t)

Answer:

d)<span>2(s-r) (t-s) </span>
3 0
3 years ago
Read 2 more answers
Consider the parametric curve:
11Alexandr11 [23.1K]

By the chain rule,

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{\frac{\mathrm dy}{\mathrm dt}}{\frac{\mathrm dx}{\mathrm dt}}=\dfrac{4\sec t\tan t}{3\sec^2t}=\dfrac43\sin t

When t=\pi, we have

\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{t=\pi}=\dfrac43\sin\pi=0

7 0
3 years ago
1. Find the common difference and find the 75th term of the arithmetic sequence: 3, 6, 9, 12, ....
Ymorist [56]

Answer:

\boxed{225}

.

Step-by-step explanation:

Arithmetic sequence

Un = a + (n - 1)b

.

First step, find its difference

b = U_2 - U_1

b = 6 - 3

b = 3

.

So, we get

a = 3

b = 3

.

Finally, Let's find the 75th term

U_{75} = 3 + (75 - 1)3

U_{75} = 3 + (74)3

U_{75} = 3 + 222

U_{75} = 225

4 0
2 years ago
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(2x+1)(x+5)<br> 6x-4xy<br> 16x^2-25
timofeeve [1]
-32xy-25 try dat anyways have a nice dayyyy byeeeee
8 0
2 years ago
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Knowing that you need a sample pool of 1019 students to ultimately get about 500 students in your sample, you are in a position
Allushta [10]

Answer:

Sampling interval = 9.323

Step-by-step explanation:

Given that:

Population size, N = 9500

Require sample, n = 1019

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Interpretation :

In other to obtain a sample of 1019 drawn systematically from the population, a sample will be drawn at every 9.323 units from the population of 9500

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