Calculate [OH - ] given [H 3 O + ] = 5.69x10 -5 M.

How can you separate a mixture of dry materials

Kruka [31]

Any substance that is not a mixture is a pure substance. When colored watercolors are applied to paper, sometimes the colors in the ink separate. This technique is called chromatography

6 0

3 years ago

Chemistry is the study of matter which is commonly defined as anything that has blank and occupies blank.

Brums [2.3K]

<span>the study of matter and the changes that matter undergoes</span>

6 0

3 years ago

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A woman informs her engineer husband that "hot water will freeze faster than cold water." He calls this statement nonsense but h

ankoles [38]

Answer:

Explanation:

It could be as a result of evaporation from the hot water causing it to have less mass than usual. Evaporation will allow the volume of the hot water to decrease and by so doing will cool faster than cold water which is at a higher mass. This is how I will explain my observations to them.

8 0

3 years ago

A food processing plant discharges 40 cfs (cubic feet per second) of process water containing an ultimate BOD (L0) of 25 mg/L an

Feliz [49]

Answer:

The right solution according to the question is provided below.

Explanation:

According to the question,

(a)

The initial conditions will be:

DO = $\frac{(40\times 1.8)+(260\times 7.6)}{40+260}$

= $\frac{2048}{300}$

= $6.826 \ mg/L$

The initial oxygen defict will be:

Do = $8.5-6.826$

= $1.674 \ mg/L$

The initial BOD will be:

Lo = $\frac{(40\times 25)+(260\times 3.6)}{40+260}$

= $\frac{1936}{300}$

= $6.453 \ mg/L$

(b)

The time reach minimum DO:

tc = $\frac{1}{(kr-kd)} ln{(\frac{0.76}{0.61} )[1-\frac{1.674(0.76-0.61)}{0.61\times 6.453} ]}$

= $\frac{1}{0.15}\times ln \ 1.158$

By putting the values of log, we get

= $0.973 \ days$

The distance to reach minimum DO will be:

Xc = $\frac{1.1\times 3600\times 24}{5280}\times 0.973 \ days$

= $18\times 0.973$

= $17.5 \ miles$

8 0

3 years ago

Solid calcium carbonate decomposes to produce solid calcium oxide and carbon dioxide gas. Express your answer as a chemical equa

Gwar [14]

Answer:

$CaCO_3(s)\rightarrow CaO(s)+CO_2(g)$

Explanation:

Hello!

In this case, when solid calcium carbonate, CaCO3 (s), is decomposed by the action of thermal energy (heat), solid calcium oxide, CaO (s) and carbon dioxide gas, CO2 (g) are yielded via the following reaction:

$CaCO_3\rightarrow CaO+CO_2$

However, since calcium carbonate is solid as well as calcium oxide and carbon dioxide is given off as a gas, we write:

$CaCO_3(s)\rightarrow CaO(s)+CO_2(g)$

Which also balanced.

Best regards!

8 0

3 years ago