Answer:
B. Both electrons of Mg should be transferred to one O.
Explanation:
Metals react by loosing electrons while non metals react by gaining electrons.
Reactions occur as each element strives to attain an octet electron configuration in the outer energy level.
It is easier for magnesium to loose 2 electrons than to gain six because loosing the two requires less energy.
Oxygen on the other hand reacts by gaining the two electrons lost by magnesium since it is easier to gain the two than to loose the six. Gaining the two electrons for oxygen requires less energy than loosing the six.
In summary, magnesium looses two electrons that are transferred to oxygen.
The 0.25 volume in liters of 1.0 M 
solution is required to provide 0.5 moles of 
(aq).
Calculation,
The Potassium carbonate dissolves as follows:
→ 
The mole ratio is 1: 2
It means, the 1 mole required to form 2 mole of (aq).
To provide 0.5 mole of (aq) = 1 mole ×0.5 mole /2 mole required by .
To provide 0.5 mole of (aq) ,0.25 mole required by .
The morality of = 1 M = number of moles / volume in lit
The morality of = 1 M = 0.25 mole/ volume in lit
Volume in lit = 0.25 mole / 1 M = 0.25 mole/mole/lit = 0.25 lit
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Answer:
(b) Calculate the molarity of a solution of 4.8 mole of HCl in 600 mL of solution. ... (g) Calculate the mass of Na2CO3 that must be used to make 700 mL of a 0.136 M Na2CO3 ... (h) What mass of NaOH is needed to make 200 mL of a 0.300 M NaOH solution? ... However, when we are reacting solutions we have to convert.
Explanation:
Answer:
T°fussion of solution is -18°C
Explanation:
We have to involve two colligative properties to solve this. Let's imagine that the solute is non electrolytic, so i = 1
First of all, we apply boiling point elevation
ΔT = Kb . m . i
ΔT = Boiling T° of solution - Boiling T° of pure solvent
Kb = ebuliloscopic constant
105°C - 100° = 0.512 °C kg/mol . m . 1
5°C / 0.512 °C mol/kg = m
9.7 mol/kg = m
Now that we have the molality we can apply, the Freezing point depression.
ΔT = Kf . m . i
Kf = cryoscopic constant
0° - (T°fussion of solution) = 1.86 °C/m . 9.76 m . 1
- (1.86°C /m . 9.7 m) = T°fussion of solution
- 18°C = T°fussion of solution
Na3PO4 + 3 KOH = 3 NaOH + K3PO4
