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igomit [66]
3 years ago
9

The valid digits in a measurement are called _____ digits.

Physics
2 answers:
Harman [31]3 years ago
8 0

Answer:

Significant

Explanation:

As the word suggests, <u>significant</u> figures or digits are numbers that are valid in measurement.

Sunny_sXe [5.5K]3 years ago
5 0

Answer:

SIGNIFICANT DIGITS

Explanation:

MARK ME BRAINLIEST PLZZZ

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An unbanked circular highway curve on level ground makes aturn
tino4ka555 [31]

Answer:

Explanation:

Given

Velocity of traffic v=60\ mi/hr\approx 26.82\ m/s

Maximum value of Centripetal force is one-tenth of weight

such that (F_c)_{max}=\frac{mg}{10}

to make a safe turn centripetal force with radius of curvature r is given by

F_c=\frac{mv^2}{r}

(F_c)_{max}=\frac{mg}{10}=F_c=\frac{mv^2}{r}

\frac{mg}{10}=\frac{mv^2}{r}

r=\frac{10v^2}{g}

r=\frac{10\times 26.82^2}{9.8}

r=733.99\approx 734\ m

     

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4 years ago
__________ were initially developed to destroy the part of the brain that controls emotions.
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It’s Lobotomies on edg.

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What is lignin and cellulose?
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I think it’s answer 1 to separate senators fr om the whims or the general public
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3 years ago
Only one of three balls A, B, and C carries a net charge q. The balls are made from conducting material and are identical. One o
Zarrin [17]

Answer:

This is greater than the initial charge, which violates the principle that the charge cannot be created or destroyed, consequently this distribution is impossible to achieve

Explanation:

The metals distribute the charge on all surface when they touch the surface increases so that charge density decreases and when the charge is separated into smaller in each metal.

Let's apply this principle to our case.

One of the spheres is loaded with a charge q, when touching a ball its charge is reduced to 1 / 2q for each ball.

         qA = ½ q

         qB = ½ q

         qC = 0

The total charge is q

we make a second contact

If we touch the ball A again with the other sphere not charged C, the chare is distributed and when separated it is reduced by half

         qA = 1/2 (q / 2) = ¼ q

         qC = ¼ q

         qB = ½ q

At this point all spheres have a charge,

      qA = ¼ q

      qb = ½ q

      qC = ¼ q

The total charge is q

Now let's contact spheres B and one of the other two

       Q = ½ q + ¼ q = ¾ q

When splitting the charge

        qB = ½ ¾ q = 3/8 q

        qC = ½ ¾ q = 3/8 q

        qA = ¼ q

The total charge is q

Note that the total load is always equal to q

Now let's analyze the given configuration

Let's look for the total load

       Q = qA + QB + QC

       Q = ½ q + 3/8 q + ¼ q

        Q = 9/8 q

This is greater than the initial charge, which violates the principle that the charge cannot be created or destroyed, consequently this distribution is impossible to achieve

8 0
3 years ago
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