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3 years ago

What is the pH value of lithium chloride?

Chemistry

1 answer:

Fiesta28 [93]3 years ago

5 0

Answer:

<h2>HERE IS YOUR ANSWER </h2>

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A compound with a formula mass of 42.08 amu is found to be 85.64 carbon and 14.36 hydrogen by mass find its molecular formula

Mars2501 [29]

brainly.com/question/8489178#respond

3 0

3 years ago

In ___ waves combine so that the resulting wave is bigger than the largest of the original waves?

Oksana_A [137]

Answer:

The answer is...

Explanation:

Constructive Interference

8 0

3 years ago

Read 2 more answers

At 2000 ∘c the equilibrium constant for the reaction 2no(g)⇌n2(g)+o2(g) is kc=2.4×103. part a if the initial concentration of no

luda_lava [24]

Answer:

[NO] = 1.72 x 10⁻³ M.

Explanation:

For the reaction:

Kc = [N₂][O₂] / [NO]².

At initial time: [NO] = 0.171 M, [N₂] = [O₂] = 0.0 M.

At equilibrium: [NO] = 0.171 M - 2x , [N₂] = [O₂] = x M.

∵ Kc = [N₂][O₂] / [NO]².

∴ 2400 = x² / (0.171 - 2x)² .

<u><em>Taking the aquare root for both sides:</em></u>

√(2400) = x / (0.171 - 2x)

48.99 = x / (0.171 - 2x)

48.99 (0.171 - 2x) = x

8.377 - 97.98 x = x

8.377 = 98.98 x.

∴ x = 8.464 x 10⁻².

3 0

3 years ago

Rank these transition metal ions in order of decreasing number of unpaired electrons.

lesya692 [45]

Answer: The given transition metal ions in order of decreasing number of unpaired electrons are as follows.

$Mn^{4+} > V^{3+} = Ni^{2+} > Fe^{3+} > Cu^{+}$

Explanation:

In atomic orbitals, the distribution of electrons of an atom is called electronic configuration.

The electronic configuration in terms of noble gases for the given elements are as follows.

Atomic number of Fe is 26.

$Fe^{3+} - [Ar] 3d^{5}$

So, there is only 1 unpaired electron present in $Fe^{3+}$ .

Atomic number of Mn is 25.

$Mn^{4+} - [Ar]3d^{3}$

So, there are only 3 unpaired electrons present in $Mn^{4+}$ .

Atomic number of V is 23.

$V^{3+} - [Ar] 3d^{2}$

So, there are only 2 unpaired electrons present in $V^{3+}$ .

Atomic number of Ni is 28.

$Ni^{2+} - [Ar] 3d^{8}$

So, there will be 2 unpaired electrons present in $Ni^{2+}$ .

Atomic number of Cu is 29.

$Cu^{+} - [Ar] 3d^{10}$

So, there is no unpaired electron present in $Cu^{+}$ .

Therefore, given transition metal ions in order of decreasing number of unpaired electrons are as follows.

$Mn^{4+} > V^{3+} = Ni^{2+} > Fe^{3+} > Cu^{+}$

Thus, we can conclude that given transition metal ions in order of decreasing number of unpaired electrons are as follows.

$Mn^{4+} > V^{3+} = Ni^{2+} > Fe^{3+} > Cu^{+}$

7 0

3 years ago

Are shrubs and small animals primary secondary or both? Are small trees primary secondary or both? These are both separate quest

In-s [12.5K]

Answer:

shrubs are producers.
small animals are primary if they eat plants only.
they're both if the consumer is omnivorous

2. most plants , including trees, are producers so they can't be consumers.

only rare plants like the venus fly trap is a consumer because they eat bugs.

5 0

4 years ago