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tangare [24]
3 years ago
6

Help pls :) I am stuck on this chemistry question about percentage yields!

Chemistry
1 answer:
Charra [1.4K]3 years ago
4 0
You just switch them around 
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What is the correct formula of Nitic acid​
Helga [31]

the formula for nitric acid is HNO3

7 0
3 years ago
2.
notka56 [123]

Answer:

417

Explanation:

50um is

50000nm

50000:120=417

7 0
3 years ago
Determine the limiting reactant in each of the following reactions:
wolverine [178]

The reactant in a chemical process known as the limiting reactant controls how much product can be produced. When the limiting reactant is completely used up, the reaction will come to an end.

<h3>Find the limiting reactant ?</h3>
  • As a result of 1 mol Sb4O6 reacting with 6 mol H2SO4, only 0.1 mol Sb4O6 reacts with 0.6 mol H2SO4, leaving only 0.5 mol H2SO4. This indicates that H2SO4 is the limiting reactant and Sb4O6 is present in excess.
  • According to your equation, which is balanced, 0.1 mol Sb4O6 should react with 0.6 mol H2SO4, yet there is only 0.5 mol H2SO4 on hand.
  • Therefore, only.083 mol of Sb4O6 are reacted.
  • The reactant that is present in the limiting amount—the limiting reactant—determines the extent to which a chemical reaction occurs.
  • The trick is really quite easy! We employ an augmented matrix to hold the data derived from the balancing equation Sb4O6 + 6H2SO4 --> 2Sb2(SO4)3 + 6H2O.
  • Although you are provided 0.5 mol of H2SO4, the reaction requires 0.6 mol. Therefore, the limiting reactant is H2SO4.
  • Only 0.0833 mol of Sb4O6 is required, but you have 0.1 mol. Sb4O6 is therefore the extra reactant.

To learn more about limiting reactant refer to:

brainly.com/question/27986321

#SPJ1

3 0
2 years ago
How many molecules are in 1.35 mol of CS2
snow_lady [41]

Answer:

There are  there are 8.13-10^25

Explanation:

N(CS2)= 1.35* (times) 6.02-10^ 25= 3.13-10^25 molecules

4 0
3 years ago
How many milliliters of a 2.00 M KBr are needed to prepare 250.0 mL of 0.60 M KBr?
PIT_PIT [208]

Answer:

75 ml

Explanation:

I did it on a Solution Calculator online.

Heres the link to the calculator to do it yourself if you want:

- https://www.sigmaaldrich.com/chemistry/stockroom-reagents/learning-center/technical-library/solution-dilution-calculator.html

7 0
3 years ago
Read 2 more answers
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