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fredd [130]
3 years ago
14

48. Explain how atoms (ions) are held together in an ionic bond. Give an example of an ionic

Chemistry
2 answers:
zalisa [80]3 years ago
3 0

Answer:

By transfer of electron from electropositive to electronegative elements

Explanation:

Examples are NaCl, MgO, Al2O3

ICE Princess25 [194]3 years ago
3 0

Answer: Atoms (ions) are held together in an ionic bond through Electrostatic attraction

Explanation: Ions are atoms that lose or gain one or more electrons to become either positively or negatively charged, which are called anions and cations respectively. The cations are usually metals while anions are usually non-metals.

The bond (ionic bond) is formed when there is a transfer of valence electron(s) between the anion and the cation in order to obtain a full valence shell for both atoms.

Example of an ionic compound is NaCl.

Where: Na is the cation that looses a valence electron to become stable to Chlorine which is the anion that gained an electron to become stable.

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Which has higher percentage of oxygen: (Fe = 56, O = 16, C = 12) a) FeO b) FeCO3 c) Fe2O3 d) Fe3O4
allochka39001 [22]

B)

FeO = 56, 16, 0

FeCO3 = 56, 48, 12

Fe2O3 = 112, 48, 0

Fe3O4 = 168, 64, 0

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What di you think you would see happen in the bucket as ice comes into contact with high kinetic energy molecules?
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Answer:The ice will melt

Explanation:

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Describe the reactions during the electrolysis of water in an electrolytic cell. Group of answer choices Oxygen and hydrogen are
Ann [662]

Answer:

Oxygen is oxidized and hydrogen is reduced.

Explanation:

Let's consider the redox reaction during the electrolysis of water in an electrolytic cell.

2 H₂O ⇒ 2 H₂ + O₂

The corresponding half-reactions are:

2 e⁻ + 2 H₂O ⇒ H₂ + 2 OH⁻

2 H₂O ⇒ O₂ + 4 H⁺ + 4 e⁻

Oxygen is oxidized since its oxidation number increases from -2 to 0.

Hydrogen is reduced since its oxidation number decreases from +1 to 0.

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134 miles= ? inches. Chemistry
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If a 28.0 L balloon with a temperature of
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Answer:

5.6 L

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We can apply Charles' Law here since our pressure is constant (will not change inside the refrigerator) and we are relating change in volume with change in temperature:

V₁ / T₁ = V₂ / T₂ where V₁ and T₁ are initial volume and temperature, and V₂ and T₂ are final volume and temperature. Let's plug in what we know and solve for the unknown:

28.0 L / 25 °C = V₂ / 5 °C => V₂ = 5.6 L

5.6 L is our new volume (at 5 °C).

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