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3 years ago

Perímetro de un cubo de 9 cm

Mathematics

1 answer:

svp [43]3 years ago

5 0

Answer:

Perímetro de

Step-by-step explanation:

What does this mean?

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9.Solve. 5a - 10 = 4a + 8Immersive Reader

aivan3 [116]

5a-10=4a+8

5a-4a=8+10

a=18

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3 years ago

Given the function f(x), what is the transformation f(x-r), is a real number and r>0?

anastassius [24]

Answer:

0 - r = the graph shifts r units left

Step-by-step explanation:

When you have 2 x intercepts of 0, -r then you shift left to negative

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3 years ago

The coefficients in the expansion of (x + y)6 are

Lostsunrise [7]

Answer:

Step-by-step explanation:

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3 years ago

You invest $15,000 in a savings account with an annual interest rate of 2.5% in

almond37 [142]

Answer:

$\$16,990.62$

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

in this problem we have

$t=5\ years\\ P=\$15,000\\ r=2.5\%=2.5/100=0.025\\n=4$

substitute in the formula above

$A=15,000(1+\frac{0.025}{4})^{4*5}$

$A=15,000(1.00625)^{20}$

$A=\$16,990.62$

5 0

3 years ago

Find the? inverse, if it? exists, for the given matrix.<br><br> [4 3]<br><br> [3 6]

True [87]

Answer:

Therefore, the inverse of given matrix is

$=\begin{pmatrix}\frac{2}{5}&-\frac{1}{5}\\ -\frac{1}{5}&\frac{4}{15}\end{pmatrix}$

Step-by-step explanation:

The inverse of a square matrix $A$ is $A^{-1}$ such that

$A A^{-1}=I$ where I is the identity matrix.

Consider, $A = \left[\begin{array}{ccc}4&3\\3&6\end{array}\right]$

$\mathrm{Matrix\:can\:only\:be\:inverted\:if\:it\:is\:non-singular,\:that\:is:}$

$\det \begin{pmatrix}4&3 \\3&6\end{pmatrix}\ne 0$

$\mathrm{Find\:2x2\:matrix\:inverse\:according\:to\:the\:formula}:\quad \begin{pmatrix}a\:&\:b\:\\ c\:&\:d\:\end{pmatrix}^{-1}=\frac{1}{\det \begin{pmatrix}a\:&\:b\:\\ c\:&\:d\:\end{pmatrix}}\begin{pmatrix}d\:&\:-b\:\\ -c\:&\:a\:\end{pmatrix}$

$=\frac{1}{\det \begin{pmatrix}4&3\\ 3&6\end{pmatrix}}\begin{pmatrix}6&-3\\ -3&4\end{pmatrix}$

$\mathrm{Find\:the\:matrix\:determinant\:according\:to\:formula}:\quad \det \begin{pmatrix}a\:&\:b\:\\ c\:&\:d\:\end{pmatrix}\:=\:ad-bc$

$4\cdot \:6-3\cdot \:3=15$

$=\frac{1}{15}\begin{pmatrix}6&-3\\ -3&4\end{pmatrix}$

$=\begin{pmatrix}\frac{2}{5}&-\frac{1}{5}\\ -\frac{1}{5}&\frac{4}{15}\end{pmatrix}$

Therefore, the inverse of given matrix is

$=\begin{pmatrix}\frac{2}{5}&-\frac{1}{5}\\ -\frac{1}{5}&\frac{4}{15}\end{pmatrix}$

4 0

3 years ago

Perímetro de un cubo de 9 cm​

Perímetro de un cubo de 9 cm