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Genrish500 [490]
3 years ago
11

When the automobile manufacturer releases a new model in its WOW series, it promises that drivers can expect to get mlleage that

varies by no more than 6.5 miles per gallon from its field-tested average of 28.4 miles per gallon. Which solution represents the range of mileage you can expect from this car?​
Mathematics
1 answer:
bixtya [17]3 years ago
8 0

Answer:

28.4 divided by 6.5

Step-by-step explanation:

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For all values of x,<br> x² + 6x - 2 = (x+p)² + q<br> Find the value of p and the value of q.
Vlad [161]

Step-by-step explanation:

{x}^{2}  + 6x - 2 =  {x}^{2}  + 2px +  {p}^{2}  + q

2p = 6

{p}^{2}  + q =   - 2

p = 3

{3}^{2}  + q =  - 2

q =  - 11

p=3, q=-11

3 0
2 years ago
In triangle xyz what is the cosine ratio of angle x
Jobisdone [24]
<span>Data:
</span><span>Hypotenuse is 7.5 
Opposite of angle x is 6</span><span>

Cosine = Side opposite (S.O) the angle on the hypotenuse (h)

We have:

</span>Cos (\alpha)x =  \frac{S.O}{h}
Cos (\alpha)x = \frac{6}{7.5}
\boxed{Cos (\alpha)x = 0.8}

<span>For better understanding, see the annex:

</span>

6 0
3 years ago
The sum of three numbers is 131. The second of three numbers is seven more than twice the first. The third number is 12 less tha
Norma-Jean [14]
First number is (x).
Second number is (2x+7).
Third number is (x-12).
Their sum is  (x+2x+7+x-12).
x+2x+7+x-12 =131

You can simplify this equation
4x-5=131,

4x=136
x=136/4=34 (first number), 
(2x+7)=34*2+7=75 (second number)
34-x=34-12 =22(third number)

Check: 34+75+22=131
6 0
3 years ago
Luis drove 308 miles on 21 gallons of gas what is his gas mileage round to the nearest MPG​
Aleksandr-060686 [28]

Answer:

15 MPG

Step-by-step explanation:

1. divide 308 by 21

2. the answer is 14.6666666

3. Rounded to the nearest MPG would be 15 as the tenth (.6) would require you to round up from 14 to 15.

5 0
3 years ago
Read 2 more answers
Which side lengths form a right triangle?
STALIN [3.7K]

Answer:

8, 15, 17  and \sqrt{2} , \sqrt{2}, 2

Step-by-step explanation:

c=\sqrt{a^2+b^2}

33=/=\sqrt{5^2+\sqrt{8}^2 }

17=\sqrt{8^2+15^2}

2=\sqrt{\sqrt{2}^2+\sqrt{2}^2  }

3 0
3 years ago
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