Question

If ="f'(x) = \frac{(x-2)^3(x^2-4)}{16}" alt="f'(x) = \frac{(x-2)^3(x^2-4)}{16}" align="absmiddle" class="latex-formula">, and $g(x) = f(x^2-1)$, what is g'(2)?
A) 2
B) 5/4
C) 5/8
D) 5/16
E) 0

Answer 1

Answer:

The answer is A

Step-by-step explanation:

Becouse the g doesnt has a answer for it,