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andrezito [222]
2 years ago
5

Help me, no links, no i don't knows. reading science sheet

Chemistry
2 answers:
Arada [10]2 years ago
6 0
The answer above is 100% right
erastovalidia [21]2 years ago
3 0

Answer:

Heat is a form of <u>energy</u> that moves from hot things to cold things. In other words, heat is energy that flows from objects with a high <u>temperature</u>. Temperature is the average <u>kinetic</u> energy of the particles in an object and is measured using a <u>thermometer</u>.

Heat can move from object to object in three ways. One way that heat flows is called <u>conduction</u>, which occurs when two objects are touching.

In conduction, the particles in the high temperature object are <u>vibrating</u> quickly compared to the low temperature object. When the particles in the high temperature object bump into the particles in the low temperature object, the low temperature object's particles begin to vibrate more quickly. Another form of heat transfer is <u>convection</u>, which occurs in <u>liquids</u> and gases. In convection, the part of the liquid or gas with high temperature is less <u>dense</u> than the part with low temperature so the high temperature parts <u>rise</u> and the low temperature parts sink.

In both conduction and convection, heat is transferred through a material. However, heat energy can also travel through empty space in a third way called <u>radiation</u>, which is how heat travels from the sun to the <u>Earth</u>.

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Answer:

158 L.

Explanation:

What is given?

Pressure (P) = 1 atm.

Temperature (T) = 112 °C + 273 = 385 K.

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Molar mass of methane CH4 = 16 g/mol.

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What do we need? Volume (V).

Step-by-step solution:

To solve this problem, we have to use ideal gas law: the ideal gas law is a single equation which relates the pressure, volume, temperature, and number of moles of an ideal gas. The formula is:

PV=nRT.

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80.0g\text{ CH}_4\cdot\frac{1\text{ mol CH}_4}{16\text{ g CH}_4}=5\text{ moles CH}_4.

So, in this case, n=5.

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V=\frac{nRT}{P}=\frac{5\text{ moles }\cdot0.0821\frac{L\cdot atm}{mol\cdot K}\cdot385K}{1\text{ atm}}=158.04\text{ L}\approx158\text{ L.}

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