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3 years ago

Explain how glucose and starch are related

Chemistry

1 answer:

weeeeeb [17]3 years ago

4 0

Answer:

Starch is the stored form of sugars in plants and is made up of a mixture of amylose and amylopectin (both polymers of glucose). ... The cells can then absorb the glucose. Starch is made up of glucose monomers that are joined by α 1-4 or α 1-6 glycosidic bonds.

Explanation:hope that helps you lots

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Label the following as either a chemical or a physical change.

Delicious77 [7]

Physical,physical, chemical, chemical, physical, chemical

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3 years ago

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Please help me to answer this question. i have to submit tomorrow.

ratelena [41]

Answer:

The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the law of conservation of mass, the mass of the products in a chemical reaction must equal the mass of the reactants.

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3 years ago

10) Give two example of where you would find elements in our daily lives.

Phoenix [80]

Carbon is found in oil and gas.
Aluminum a light metal used in making pots and pans.
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3 years ago

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Flura [38]

Answer:

Glucose and oxygen are required for cellular respiration. As the law of conversation states, in a biochemical reaction, mass is conserved. The mass of hydrogen in the glucose is therefore conserved in the water molecules products.

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3 years ago

In reality, a hydrate of iron(III) nitrate had to be used, not the anhydrous salt. As you may guess, some of the hydrate’s mass

liq [111]

Answer: The mass of nonahydrate iron (III) nitrate is 16.2 g

Explanation:

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of $Fe(NO_3)_3$ = 0.0020 M

Volume of solution = 2 L

Putting values in above equation, we get:

$0.0200M=\frac{\text{Moles of }Fe(NO_3)_3}{2L}\\\\\text{Moles of }Fe(NO_3)_3=(0.0200mol/L\times 2L)=0.04mol$

The chemical equation for the decomposition of hydrated iron (III) nitrate follows:

$Fe(NO_3)_3.9H_2O\rightarrow Fe(NO_3)_3+9H_2O$

By Stoichiometry of the reaction:

1 mole of iron (III) nitrate is produced from 1 mole of hydrated iron (III) nitrate

So, 0.04 moles of iron (III) nitrate will be produced from = $\frac{1}{1}\times 0.04=0.04mol$ of hydrated iron (III) nitrate

To calculate the mass from given number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of nonahydrate iron (III) nitrate = 404.0 g/mol

Moles of nonahydrate iron (III) nitrate = 0.04 moles

Putting values in above equation, we get:

$0.04mol=\frac{\text{Mass of nonahydrate iron (III) nitrate}}{404.0g/mol}\\\\\text{Mass of nonahydrate iron (III) nitrate}=(0.04mol\times 404.0g/mol)=16.2g$

Hence, the mass of nonahydrate iron (III) nitrate is 16.2 g

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3 years ago