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Sergeu [11.5K]
4 years ago
15

How many of the elements in the second row of the periodic table (li through ne) will have at least one unpaired electron in the

ir electron configurations?
Chemistry
1 answer:
nexus9112 [7]4 years ago
4 0
The second row of the periodic table consists of the elements:
Lithium (3)
Beryllium (4)
Boron (5)
Carbon (6)
Nitrogen (7)
Oxygen (8)
Fluorine (9)
Neon (10)

The number in the bracket shows the atomic number of the elements, which also indicates the number of electrons they have. We see that the odd numbered elements, Li, B, N and F will all have unpaired electrons. Therefore, 4 elements will have unpaired electrons in their electronic configuration.
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Electrolysis is used in the electroplating of metals. The same amount of current is passed through separate aqueous solutions of
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CuSO4 cell will have the greatest amount of deposit among all three. The deposit will occur at the cathode

Explanation:

The valence of the elements in this case is as follows -

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CuSO4 cell will have the greatest amount of deposit among all three

The atoms of copper metal will deposit at the cathode. At the cathode, the least number of moles of electrons needed .

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