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Dmitry_Shevchenko [17]
2 years ago
13

Solve for x. 4x - 36 3x + 10

Mathematics
1 answer:
Anestetic [448]2 years ago
7 0

Answer:

x = 46

Step-by-step explanation:

Since the angles are equal to each other, make the equations equal to each other.

4x - 36 = 3x + 10 and simplify

x - 36 = 10

x = 46

Hope this helps!

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Y=<br> (0.<br> (1,<br> (2,<br> (3.<br> (4,<br> (5,
skad [1K]

Answer:

y = (0, 1, 32, 243, 1024, 3125)

3 0
3 years ago
Can someone help me with these 4 geometry questions? Pls it’s urgent, So ASAP!!!!
blagie [28]

<u>Question 4</u>

1) \overline{BD} bisects \angle ABC, \overline{EF} \perp \overline{AB}, and \overline{EG} \perp \overline{BC} (given)

2) \angle FBE \cong \angle GBE (an angle bisector splits an angle into two congruent parts)

3) \angle BFE and \angle BGE are right angles (perpendicular lines form right angles)

4) \triangle BFE and \triangle BGE are right triangles (a triangle with a right angle is a right triangle)

5) \overline{BE} \cong \overline{BE} (reflexive property)

6) \triangle BFE \cong \triangle BGE (HA)

<u>Question 5</u>

1) \angle AXO and \angle BYO are right angles, \angle A \cong \angle B, O is the midpoint of \overline{AB} (given)

2) \triangle AXO and \triangle BYO are right triangles (a triangle with a right angle is a right triangle)

3) \overline{AO} \cong \overline{OB} (a midpoint splits a segment into two congruent parts)

4) \triangle AXO \cong \triangle BYO (HA)

5) \overline{OX} \cong  \overline{OY} (CPCTC)

<u>Question 6</u>

1) \angle B and \angle D are right angles, \overline{AC} bisects \angle BAD (given)

2) \overline{AC} \cong \overline{AC} (reflexive property)

3) \angle BAC \cong \angle CAD (an angle bisector splits an angle into two congruent parts)

4) \triangle BAC and \triangle CAD are right triangles (a triangle with a right angle is a right triangle)

5) \triangle BAC \cong \triangle DCA (HA)

6) \angle BCA \cong \angle DCA (CPCTC)

7) \overline{CA} bisects \angle ACD (if a segment splits an angle into two congruent parts, it is an angle bisector)

<u>Question 7</u>

1) \angle B and \angle C are right angles, \angle 4 \cong \angle 1 (given)

2) \triangle BAD and \triangle CAD are right triangles (definition of a right triangle)

3) \angle 1 \cong \angle 3 (vertical angles are congruent)

4) \angle 4 \cong \angle 3 (transitive property of congruence)

5) \overline{AD} \cong \overline{AD} (reflexive property)

6) \therefore \triangle BAD \cong \triangle CAD (HA theorem)

7) \angle BDA \cong \angle CDA (CPCTC)

8) \therefore \vec{DA} bisects \angle BDC (definition of bisector of an angle)

8 0
2 years ago
What is the vaule of 0.77
padilas [110]
<span>seventy-seven hundredths.</span>
3 0
3 years ago
Ethan's taxable income is $87,525. Use this tax schedule to calculate the total amount he owes in taxes.
Reptile [31]
$18,617.75 is the answer
$87,525-$77,100=$10,425 (the amount over $77,100)
$10,425 x .28=$2,919 (the 28% taxed amount over $77,100)
$2,919+$15,698.75 (the already taxed amount in the chart)=$18,617.75



8 0
3 years ago
Please help!! I can’t figure this out
Rudiy27
Each room has 2 walls that are 4x10 = 40 square feet and 2 walls that are 8x10 = 80 square feet. So 80+80+40+40 = 240 square feet of wall will be painted per room.

We use 2 coats of paint so in effect, we double the area. Imagine laying one thin wall on top of the other. The amount of paint area used per room doubles from 240 to 480

There are 4 of these rooms so 4*480 = 1920

The total area we need to paint is 1920 square feet

Divide this over 32 to get 1920/32 = 60

Final Answer: 60
5 0
3 years ago
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