Answer:
There are 10 blocks in a row (section). There are 6 rows (sections).
1.
A. If each block has a value of one, what is the value for a section of blocks?
<h2>
10</h2>
There are 10 blocks in a section. 10 * 1 = 10
B. What is the total value of all the blocks, write an equation?
<h2>60</h2>
There are 6 sections. There are 10 blocks in a section. 6 * 10 * 1 = 60
2.
A. If each block has a value of ten, what is the value for a section of blocks?
<h2> 100</h2>
There are 10 blocks in a section. 10 * 10 = 100
B. What is the total value of all the blocks, write an equation?
<h2>600</h2>
There are 6 sections. There are 10 blocks in a section. 60 * 10 * 10 = 600
Answer:
10
Step-by-step explanation:
find the length of each leg, being 6 and 8. Then use the pythagorean theorem a^2+b^2=c^2
6^2+8^2=c^2
36+64=c^2
100=c^2
c=10
hope this helped... if it did, please let me know by marking me the brainliest:))
notice, the first term is 9.5
from there it goes to 11.5, well, how much is it being added to get 11.5?
well 9.5 + 2, is 11.5, so it was added 2 to 9.5
then it goes from 11.5 to 13.5, namely, 11.5+2 = 13.5
and then 13.5+2 = 15.5 and so on
so, the "common difference" or the common addition value, is 2
how do you find the nth term?
well
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Answer: y = 25
Explanation:
2x+5 = 3x - 33
x = 38
2x+5 + 4y-1 = 180
2(38) + 5 + 4y - 1 = 180
y = 25
I hope this helped!
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