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Pavel [41]
3 years ago
8

A store is selling 4 dozen doughnuts for 24$. Based on this price, how many doughnuts could you buy for 1$

Mathematics
2 answers:
Vlad1618 [11]3 years ago
6 0

Answer:

2

Step-by-step explanation:

So first, you know that 4 dozen doughnuts = 48 doughnuts. Next, to find how much you could get for one dollar you have the ratio $24:48 doughnuts and you can divide both sides of this ratio by 24 to get $1:2 doughnuts.

stealth61 [152]3 years ago
5 0
6$ because 24$ divided by 4 equals 6
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P divided by 5 equals -32
Lostsunrise [7]

Answer:

p = -160

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define</u>

p/5 = -32

<u>Step 2: Solve for </u><em><u>p</u></em>

  1. Multiply 5 on both sides:                     p = -160
6 0
3 years ago
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On Monday, Deborah ran 3 2− 5miles and on Tuesday she ran 4 1− 5miles. How many miles did she run on these two days together?
notsponge [240]

Mixed fraction:

3 2/5 = 17/5

4 4/5 = 24/5

Miles she ran:

17/5 + 24/5

= 41/5 miles or 8.2 miles

6 0
3 years ago
Which pairs of triangles can be shown to be congruent using rigid motions?
andreyandreev [35.5K]

Two figures are congruent if and only if there exists one or more rigid motions which will map one figure onto the other.

1. Triangles ABC and MNP are not congruent.

2. Triangles ABC and EFG are not congruent

3. Triangles ABC and STU are congruent.

4. Triangles EFG and MNP are congruent.

5. Triangles EFG and STU are not congruent.

6. Triangles STU and MNP are not congruent.

7 0
3 years ago
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Log(x-2)+log2=2logy<br>log(x-3y+3)=0​
In-s [12.5K]

Answer:

<h2>x = 4 and y = 2 or x = 10 and y = 4</h2>

Step-by-step explanation:

\left\{\begin{array}{ccc}\log(x-2)+\log2=2\log y&(1)\\\log(x-3y+3)=0&(2)\end{array}\right

===========================\\\text{DOMAIN:}\\\\x-2>0\to x>2\\y>0\\x-3y+3>0\to x-3y>-3\\=====================\\\\\text{We know:}\ \log_ab=c\iff a^c=b,\\\\\text{therefore}\ \log_ab=0\iff a^0=b\to b=1\\\\\text{From this we have}\\\\\log(x-3y+3)=0\iff x-3y+3=1\qquad\text{add}\ 3y\ \text{to both sides}\\\\x+3=3y+1\qquad\text{subtract 3 from both isdes}\\\\\boxed{x=3y-2}\qquad(*)\\\\\text{Substitute it to (1)}

\log(3y-2-2)+\log2=2\log(y)\qquad\text{use}\ \log_ab^n=n\log_ab\\\\\log(3y-4)+\log2=\log(y^2)\qquad\text{subtract}\ \log(y^2)\ \text{from both sides}\\\\\log(3y-4)+\log2-\log(y^2)=0\\\\\text{Use}\ \log_ab+\log_ac=\log_a(bc)\ \text{and}\ \log_ab-\log_ac=\log_a\dfrac{b}{c}\\\\\log\dfrac{(3y-4)(2)}{y^2}=0\qquad\text{use}\ \log_ab=0\Rightarrow b=1\\\\\dfrac{(3y-4)(2)}{y^2}=1\iff y^2=(3y-4)(2)\\\\\text{Use the distributive property}\ a(b+c)=ab+ac

y^2=(3y)(2)+(-4)(2)\\\\y^2=6y-8\qquad\text{subtract}\ 6y\ \text{from both sides}\\\\y^2-6y=-8\qquad\text{add 8 to both sides}\\\\y^2-6y+8=0\\\\y^2-2y-4y+8=0\\\\y(y-2)-4(y-2)=0\\\\(y-2)(y-4)=0\iff y-2=0\ \vee\ y-4=0\\\\\boxed{y=2\ \vee\ y=4}\in D

\text{Put the values of}\ y\ \text{to }\ (*):\\\\\text{for}\ y=2:\\\\x=3(2)-2\\\\x=6-2\\\\\boxed{x=4}\in D\\\\\text{for}\ y=4:\\\\x=3(4)-2\\\\x=12-2\\\\\boxed{x=10}\in D

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6. Craig and James both live 4 miles up a hill. Craig hikes uphill at a rate of 1 mile every two hours.
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Answer:

James

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James rate:

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2x = 2

x = 1 hour

Rate = distance/time = 4/1 = 4 miles per hour

Craig's rate = 1/2 = 0.5 miles per hour

James is faster

6 0
3 years ago
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