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Nataliya [291]
3 years ago
14

If we decrease the distance an object moves we will (2 points)

Physics
2 answers:
Fantom [35]3 years ago
8 0
Decrease the amount of force applied
Amanda [17]3 years ago
6 0
Work done = force × displacement

If we decrease the distance an object moves

displacement will decrease.

Thus work done will decrease.

Force will not be affected.
____________________

Thus your answer is : decrease the amount of work done.
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Answer:I would prefer ginger with lemon and honey tea...Stay hydrated,Rest,

Explanation:

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A granite monument has a volume of 25,365.4 cm3. The density of granite is 2.7 g/cm3. Use this information to calculate the mass
Nana76 [90]
V = 25,364.4 cm^3   Is volumer = 2.7g/cm^3      Is density
To calculate mass you use formula:m= V*rTo avoid remembering this formula you can see the type of unit on each given variable. We can see that we have g/cm^3 and cm^3. If we multiply them, we negate cm^3 and cm^3 and we are left with g which is unit for mass.
the answer is :
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6 0
3 years ago
What is the concentration of OH– ions at a pH = 6?
makkiz [27]
<h3><u>Answer;</u></h3>

1 × 10^-8 M

<h3><u>Explanation</u>;</h3>

pH is given by the -log[H+] while

pOH is given by the -log[OH-]

But;

pH + pOH = 14

Thus; if pH is 6, then pOH = 8

pOH = 8

-log[OH-] = 8

[OH-] = 10^-8 M

The concentration of OH- ions at a pH of 6 is 1 × 10^-8 M

8 0
3 years ago
A physics teacher performing an outdoor demonstration suddenly falls from rest off a high cliff and simultaneously shouts help.
GrogVix [38]

Answer:

H = 532 m

Explanation:

When teacher falls into the cliff then she shout for Help at the same time

so here we know that sound will go down and reflect back up

so here in 3 s distance traveled by the sound

d = vt

d = 340 \times 3

d = 1020 m

now in the same time the distance that teacher will fall down is given as

d_1 = \frac{1}{2}gt^2

d_1 = \frac{1}{2}(9.81)(3^2)

d_1 = 44.1 m

now total distance traveled by teacher and sound in 3 s

d_{total} = d + d_1

d_{total} = 1020 + 44.1

this total distance must be equal to twice the height of the cliff

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H = 532 m

7 0
3 years ago
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In preparation for the final exam, our astronomy study group has reconvened to discuss Mercury's unique orbital properties. They
grigory [225]

Answer:

The only incorrect statement is from student B

Explanation:

The planet mercury has a period of revolution of 58.7 Earth days and a rotation period around the sun of 87 days 23 ha, approximately 88 Earth days.

Let's examine student claims using these rotation periods

Student A. The time for 4 turns around the sun is

           t = 4 88

           t = 352 / 58.7 Earth days

In this time I make as many rotations on itself each one with a time to = 58.7 Earth days

           #_rotaciones = t / to

           #_rotations = 352 / 58.7

           #_rotations = 6

therefore this statement is TRUE

student B. the planet rotates 6 times around the Sun

          t = 6 88

          t = 528 s

The number of rotations on itself is

           #_rotaciones = t / to

           #_rotations = 528 / 58.7

           #_rotations = 9

False, turn 9 times

Student C. 8 turns around the sun

           t = 8 88

           t = 704 days

the number of turns on itself is

            #_rotaciones = t / to

            #_rotations = 704 / 58.7

            #_rotations = 12

True

The only incorrect statement is from student B

6 0
2 years ago
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