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Mashutka [201]
3 years ago
7

In the following diagram, the voltage is 1.5 volts and the resistance is 7.5 ohms. Use Ohm's law to determine the current in the

circuit.
11.3 amps
5.0 amps
6.0 amps
0.2 amps
Physics
2 answers:
Maru [420]3 years ago
8 0
I=V/R

I=1.5/7.5

I=0.2

The answer is 0.2
dybincka [34]3 years ago
7 0

Answer:

Current in the circuit, I = 0.2 amps

Explanation:

It is given that,

Voltage of the circuit, V = 1.5 volts

Resistance, R = 7.5 ohms

According to Ohm's law, the voltage is equal to the product of current and the resistance.

i.e. I=\dfrac{V}{R}

V is the voltage across the circuit

R is the resistance in the circuit

I=\dfrac{1.5\ V}{7.5\ \Omega}

I = 0.2 amps

Hence, the correct option is (d).

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Suppose that the electric field in the Earth's atmosphere is E = 8.60 101 N/C, pointing downward. Determine the electric charge
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Answer:

q = 3.87 x 10⁵ C

Explanation:

given,

Electric field, E = 8.60 x 10¹ = 86 N/C

radius of earth, R = 6371 Km = 6.371 x 10⁶ m

Coulomb constant, K = 9 x 10⁹ N · m²/C²

Charge on the earth = ?

the electric field at the point

E =\dfrac{kq}{r^2}

q =\dfrac{Er^2}{k}

inserting all the values

q =\dfrac{86\times (6.371\times 10^6)^2}{9\times 10^{9}}

      q = 3.87 x 10⁵ C

The electric charge on the earth is equal to 3.87 x 10⁵ C

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You drop a small ball, and then a second small ball. When you drop the second ball, the distance between them is 3 cm. What stat
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Answer:

c) The distance between the balls increases.

Explanation:

If you drop the balls at the same time, regardless of their masses they accelerate equally, since they will be in free fall.

However, if you drop one of the balls earlier, then that ball will gain velocity, whereas the second ball has zero initial velocity. At the time the second ball is dropped, both balls have the same acceleration but different initial velocities.

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Answer:

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Water has a mass per mole of 18.0 g/mol, and each water molecule (H20) has 10 electrons. (a) How many electrons are there in one
Allushta [10]

Answer:

total number of electron in 1 litter is 3.34 × 10^{26} electron

Explanation:

given data

mass per mole = 18 g/mol

no of electron = 10

to find out

how many electron in 1 liter of water

solution

we know molecules per gram mole is 6.02 ×10^{23} molecules

no of moles is 1

so

total number of electron in water is = no of electron ×molecules per gram mole × no of moles

total number of electron in water is = 10 × 6.02 ×10^{23} × 1

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and

we know

mass = density × volume    ..........1

here we know density of water is 1000 kg/m

and volume = 1 litter = 1 × 10^{-3} m³

mass of 1 litter = 1000 × 1 × 10^{-3}

mass = 1000 g

so

total number of electron in 1 litter =  mass of 1 litter × \frac{molecules per gram mole}{mass per mole}

total number of electron in 1 litter =  1000 × \frac{6.02*10{24}}{18}

total number of electron in 1 litter is 3.34 × 10^{26} electron

8 0
3 years ago
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