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Mashutka [201]
3 years ago
7

In the following diagram, the voltage is 1.5 volts and the resistance is 7.5 ohms. Use Ohm's law to determine the current in the

circuit.
11.3 amps
5.0 amps
6.0 amps
0.2 amps
Physics
2 answers:
Maru [420]3 years ago
8 0
I=V/R

I=1.5/7.5

I=0.2

The answer is 0.2
dybincka [34]3 years ago
7 0

Answer:

Current in the circuit, I = 0.2 amps

Explanation:

It is given that,

Voltage of the circuit, V = 1.5 volts

Resistance, R = 7.5 ohms

According to Ohm's law, the voltage is equal to the product of current and the resistance.

i.e. I=\dfrac{V}{R}

V is the voltage across the circuit

R is the resistance in the circuit

I=\dfrac{1.5\ V}{7.5\ \Omega}

I = 0.2 amps

Hence, the correct option is (d).

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Explanation:

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a body of mass 0.2kg is whirled round a horizontal circle by a string inclined at 30 degrees to the vertical calculate &lt;br /&
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Answer:

a)  T = 2.26 N, b) v = 1.68 m / s

Explanation:

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Let's set a reference system where the x-axis is radial and the y-axis is vertical, let's decompose the tension of the string

        sin 30 = \frac{T_x}{T}

        cos 30 = \frac{T_y}{T}

        Tₓ = T sin 30

        T_y = T cos 30

Y axis  

       T_y -W = 0

       T cos 30 = mg                     (1)

X axis

        Tₓ = m a

they relate it is centripetal

        a = v² / r

we substitute

         T sin 30 = m\frac{v^2}{r}            (2)

a) we substitute in 1

         T = \frac{mg }{cos 30}

         T = \frac{ 0.2 \ 9.8}{cos  \ 30}

         T = 2.26 N

b) from equation 2

           v² = \frac{T \ sin 30 \ r}{m}

If we know the length of the string

          sin 30 = r / L

          r = L sin 30

we substitute

          v² = \frac{ T \ sin 30 \ L \ sin 30}{m}

          v² = \frac{TL \ sin^2  30}{m}

For the problem let us take L = 1 m

let's calculate

          v = \sqrt{ \frac{2.26 \ 1 \ sin^230}{0.2} }

          v = 1.68 m / s

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