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8090 [49]
3 years ago
10

Write the following temperatures in ᵒC and ᵒFThank you for helping!​

Chemistry
1 answer:
Ilya [14]3 years ago
3 0
1) 20°c and 68°f. 2) 16°c and 61°f
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Starting with 0.657 g of lead(II) nitrate, a student collects 0.925 g of precipitate. If the calculated mass of precipitate is 0
tatuchka [14]

Answer:

101.2%

Explanation:

Given:

Theoretical yield of the precipitate = 0.914 g

Actual yield of the precipitate = 0.925 g

Now, the percent yield is given as a ratio of actual yield by theoretical yield expressed as a percentage.

Framing in equation form, we have:

\%\ yield=\frac{Actual\ yield}{Theoretical\ yield}\times 100

Now, plug in 0.925 g for actual yield, 0.914 g for theoretical yield and solve for % yield. This gives,

\%\ yield=\frac{0.925\ g}{0.914\ g}\times 100\\\\\%\ yield=1.012\times 100\\\\\%\ yield=101.2\%

Therefore, the percent yield is 101.2%.

5 0
4 years ago
What is endothermic process?​
LiRa [457]

Answer:

An endothermic process is any process with an increase in the enthalpy H (or internal energy U) of the system. In such a process, a closed system usually absorbs thermal energy from its surroundings, which is heat transfer into the system. It may be a chemical process, such as dissolving ammonium nitrate in water, or a physical process, such as the melting of ice cubes.

7 0
3 years ago
Which statement about common descent is correct?
ludmilkaskok [199]
Hey, What are the options can’t see anything!
7 0
3 years ago
In modern atomic theory, bohr's orbits are replaced by atomic orbitals. what is an atomic orbital?
Darya [45]

Bohr's theory states that the motion of the electron (particle) around the nucleus is very much similar to motion of the planets around the sun in the solar system. Both in the mathematical and physical sense.

The Bohr's Atomic theory only explains the motion of the electrons in discrete atomic orbitals that are predicted by the Bohr's equation.

It strictly implies that the electron only exists in these discreet orbitals and fails to explain anything about the nature of the electron in between the discrete orbitals.

The modern atomic theory does not share this limitation as it does not impose the electron to only occupy the discrete orbitals and neither does it impose particle nature upon the electron.

In the modern theory does not focus on describing the motion of the electron around the orbital but rather the probability of finding an electron around the nucleus. The modern atomic orbitals or electron clouds are the regions in which the probability of finding the electron is the highest when the wave function collapses.  The Schrödinger's wave equation explains the evolution of the wave function in time. Hence enabling us to predict the future possible locations of the electron but never the exact location as that is impossible due to the Heisenberg's Uncertainty principle.

Learn more about Bohr's atomic orbitals by clicking here :

brainly.com/question/11872378

#SPJ4

4 0
2 years ago
Carbon dioxide dissolves in water to form carbonic acid, which is primarily dissolved CO2. Dissolved CO2 satisfies the equilibri
lorasvet [3.4K]

Explanation:

The reaction equation will be as follows.

           CO_{2}(aq) + H_{2}O \rightleftharpoons H^{+}(aq) + HCO^{-}_{3}(aq)

Calculate the amount of CO_{2} dissolved as follows.

             CO_{2}(aq) = K_{CO_{2}} \times P_{CO_{2}}

It is given that K_{CO_{2}} = 0.032 M/atm and P_{CO_{2}} = 1.9 \times 10^{-4} atm.

Hence, [CO_{2}] will be calculated as follows.

           [CO_{2}] = K_{CO_{2}} \times P_{CO_{2}}          

                           = 0.032 M/atm \times 1.9 \times 10^{-4}atm

                           = 0.0608 \times 10^{-4}

or,                        = 0.608 \times 10^{-5}

It is given that K_{a} = 4.46 \times 10^{-7}

As,      K_{a} = \frac{[H^{+}]^{2}}{[CO_{2}]}

          4.46 \times 10^{-7} = \frac{[H^{+}]^{2}}{0.608 \times 10^{-5}}  

               [H^{+}]^{2} = 2.71 \times 10^{-12}

                      [H^{+}] = 1.64 \times 10^{-6}

Since, we know that pH = -log [H^{+}]

So,                      pH = -log (1.64 \times 10^{-6})

                                 = 5.7

Therefore, we can conclude that pH of water in equilibrium with the atmosphere is 5.7.

3 0
3 years ago
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