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Phoenix [80]
3 years ago
15

How many of the following molecules are polar? Pcl5 cos xeo3 sebr2

Chemistry
1 answer:
klasskru [66]3 years ago
5 0

Answer:

<em>Three (3) of the molecules are polar: </em>CoS,<em> </em>XeO_{3},<em> </em>SeBr_{2}<em>.</em>

Explanation:

Polar substances have their elements held together by a covalent bond that contain partially positive and negative charges, which results in a difference in the charges' electronegativity difference (usually ranging between 0.4 and 0.7).

  • PCl5 is <u>non-polar</u> with a symmetric geometry
  • CoS is <u>polar</u>
  • XeO3 is <u>polar</u>, with a trigonal pyramidal molecular geometric
  • SeBr2 is <u>polar</u> as the difference their electronegativity is about ).5
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What hybridization is required for central atoms that have a tetrahedral arrangement of electron pairs? A trigo- nal planar arra
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Answer:

sp³;

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None;

One;

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Explanation:

The central atom in a molecule is generally the one that can make a greater number of bonds. The covalent bonds are made by the sharing of electrons, and, for that, the electron must be alone in the orbital.

To explain this, the hybridization theory was created, which states that, the orbitals are joined to form hybrids ones, and so, by the Hund's law, the electrons are alone in them.

The sigma bonds are done in the hybrids orbitals, and at the pure orbitals, the pi bonds are done. The lone pair of electrons are at a pure orbital. So, to know the hybridization of the central atom, we must know how many sigma bonds it does, and it will be the number of hybrids orbitals (each orbital may have two electrons, thus each bond are done in one orbital).

Double bonds and triple bonds have always only one sigma bond, so the number of sigma bonds is equal to the number of bonds, it's not necessary to know if they are simple, double or triple.

When the arrangement is tetrahedral, the central atom does 4 bonds, so it has 4 sigma bonds, and 4 hybrids orbitals (one of s and three for p), does its hybridization is sp³. Because exists only 3 p orbitals, there are no unhybridized p orbitals in this case.

When the arrangement is trigonal, the central atom does 3 bonds, so it has 3 hybrids orbitals (one of s and two of p), thus the hybridization is sp². So there are one unhybridized p orbitals.

When the arrangement is linear, the central atom does 2 bonds, so it has 2 hybrids orbitals (one of s and one of p), thus the hybridization is sp. So, there are two unhybridized p atoms.

As stated before, the unhybridized p orbitals are used to pi bonds.

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