Answer:- The functions f(x) and g(x) are equivalent.
Explanation:-
Given functions:- 
and ![g(x)=\sqrt[3]{64^x }](https://tex.z-dn.net/?f=g%28x%29%3D%5Csqrt%5B3%5D%7B64%5Ex%20%7D)
Simplify the functions by using law of exponents
Thus 
and ![g(x)=\sqrt[3]{64^x}=\sqrt[3]{(4^3)^x}= \sqrt[3]{4^{3x}}= \sqrt[3]{(4^x)^3}=4^x](https://tex.z-dn.net/?f=g%28x%29%3D%5Csqrt%5B3%5D%7B64%5Ex%7D%3D%5Csqrt%5B3%5D%7B%284%5E3%29%5Ex%7D%3D%20%5Csqrt%5B3%5D%7B4%5E%7B3x%7D%7D%3D%20%5Csqrt%5B3%5D%7B%284%5Ex%29%5E3%7D%3D4%5Ex)
⇒f(x)=g(x)
Therefore ,the functions f(x) and g(x) are equivalent.
You can either convert -3 into a fraction, or convert -2/5 into a decimal so you can solve this.
If you decide to convert -3, into a fraction, it would be -3/1, and you'd have to multiply that by the reciprocal of -2/5.
So, you'd have -3/1(-5/2)=15/2, which can be simplified to 7 1/2.
If you decide to convert -2/5 into a decimal, you would get -0.4. You would then divide -3 by -0.4, which is equal to 7.5.
Both 7.5 and 7 1/2 are correct answers, and if you were to convert 7.5 into a fraction and 7 1/2 into a decimal, you would notice that they are the same number, but in different forms.
