We can solve for both x and y of System A and B to compare the values of x.
System A. Multiply by 4 the first equation and add both equations,
12x + 8y = 12
+ -2x - 8y = -1
We will be left with equation,
10x = 11
The value of x is 11/10
System B. Multiply the first equation by -2 and add the equations,
2x + 28y = -2
+ -2x - 8y = -1
We will be left with 20y = -3. Substitute the value of y to any of the equations. This gives a value of x equal to 11/10.
The answer therefore is that both systems will have the same value of x's.
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