V=IR therefore I=V/R=10/50=0.2A therefore the current is 0.2 A
-- During the time the ball is flying from the high roof to the low roof,
it's going to fall (100-25) = 75 meters.
How long does it take an object dropped from rest to fall 75 meters ?
Distance = (1/2) · (gravity) · (time)²
75 m = (4.9 m/s²) · (time)²
Time² = (75 m) / (4.9 m/s²)
Time² = 15.31 sec²
Time = √(15.31 sec²) = 3.91 seconds
So the ball has to cover the horizontal distance of 20 meters
in 3.91 seconds.
Distance = (speed) · (time)
20 m = (speed) · (3.91 sec)
Speed = (20 m) / (3.91 sec)
Speed = 5.11 m/s
Answer:
4m East
Explanation:
26-29= -3 (so that means 3m west)
-3+7= 4 (so 4m East)
hope it helps
Complete question:
A small 175-g ball on the end of a light string is revolving uniformly on a frictionless surface in a horizontal circle of diameter 1.0 m. The ball makes 2.0 revolutions every 1.0 s. What are the magnitude and direction of the acceleration of the ball?
Answer:
The acceleration of the ball is 78.98 m/s², directed inwards
Explanation:
Given;
mass of the ball, m = 175 g
radius of the circle, r = 0.5 m
angular speed of the ball, ω = 2 rev/s
The magnitude of the centripetal acceleration of the ball is calculated as follows;

The centripetal acceleration is directed inwards.
Answer:
8 J
Explanation:
Given : Force = 2 N
Distance = 4m
Work done = force * distance
Work done = 2 * 4 = 8 J