The diagram is missing; however, we know that the intensity of a sound wave is inversely proportional to the square of the distance from the source:
where I is the intensity and r is the distance from the source.
We can assume for instance that the initial distance from the source is r=1 m, so that we put
The intensity at r=3 m will be
Therefore, the sound intensity has decreased by a factor
.
Answer:
Telegraph distance will be 9.6 mile
Explanation:
We have given the voltage V = 9 volt
Contact resistance = 4 ohm
Relay resistance = 80 ohm
And wire has a resistance = 10 ohm/mile
We have given the current = 50 mA =0.05 A
According to ohm's law 
So the resistance of wire = 180-4-80=96 ohm
So the length of the telegraph distance will be 
Answer:
In both cases, the sound and spelling are the same, and only the definition changes. Here are 30 more examples of homonyms. Note that some homonyms have more than two meanings (for example, "tender" can also mean sensitive, easily chewed, or even refer to chicken strips), but to keep things simple we've only included two in our homonyms list:
Complete Question:
A machinist turns the power on to a grinding wheel, which is at rest at time t = 0.00 s. The wheel accelerates uniformly for 10 s and reaches the operating angular velocity of 25 rad/s. The wheel is run at that angular velocity for 37 s and then power is shut off. The wheel decelerates uniformly at 1.5 rads/s2 until the wheel stops. In this situation, the time interval of angular deceleration (slowing down) is closest to
Answer:
t= 16.7 sec.
Explanation:
As we are told that the wheel is accelerating uniformly, we can apply the definition of angular acceleration to its value:
γ = (ωf -ω₀) / t
If the wheel was at rest at t-= 0.00 s, the angular acceleration is given by the following equation:
γ = ωf / t = 25 rad/sec / 10 sec = 2.5 rad/sec².
When the power is shut off, as the deceleration is uniform, we can apply the same equation as above, with ωf = 0, and ω₀ = 25 rad/sec, and γ = -1.5 rad/sec, as follows:
γ= (ωf-ω₀) /Δt⇒Δt = (0-25 rad/sec) / (-1.5 rad/sec²) = 16.7 sec
Answer:
B) 40 km West
Explanation:
Let position of B is origin so with respect of City B the position of A is given as
south of city B
now Bus starts from City A and travels a distance of 50 km at 37 degree North of East to reach city C
so it is
now the position of C is given with respect to A
in order to find the position of C with respect to B we can say
so in order to reach at city B from city C bus has to travel 40 km towards West
