Answer:
the correct solution is 13 s
Explanation:
This is a kinematic problem, let's use accelerated rectilinear motion relationships.
For the first car it has an accelerometer of 2.0 m/s²
x = v₀₁ t + ½ a₁ t²
The second car leaves the same point, but 4.0 seconds later
x = v₀₂ (t-4) + ½ a₂ (t-4)²
With this form we use the same time for both cars.
The initial speeds are zero for both vehicles leave the rest, at the point where they are located has the same position
x = ½ a₁ t²
x = ½ a₂ (t-4)²
Let's solve
a₁ t² = a₂ (t-4)²
a₁/a₂ t² = t² -2 4 t + 16
t² (1- 2.0 / 4.0) - 8 t +16
t² 0.5 - 8 t +16 = 0
t² -16 t + 32 = 0
Let's solve the second degree equation
t = [16 ±√( 16² - 4 32)] / 2
t = ½ (16 ± 11,3)
Solutions
t1 = 13.66 s
t2 = 2.34 s
These are the mathematical solutions for the meeting point, but car 2 leaves after 4 seconds, so the only solution is 13.66 s
the correct solution is 13 s, if you have to select one the nearest 12s
Larger molecules will move slower and smaller molecules will move faster. Did this answer your question?
<span>The offspring will have the exact same genetic makeup as the parent. This is because there is no other parent involved other than the one parent.</span>
Answer:
a) The centripetal acceleration of the car is 0.68 m/s²
b) The force that maintains circular motion is 940.03 N.
c) The minimum coefficient of static friction between the tires and the road is 0.069.
Explanation:
a) The centripetal acceleration of the car can be found using the following equation:
Where:
v: is the velocity of the car = 51.1 km/h
r: is the radius = 2.95x10² m
Hence, the centripetal acceleration of the car is 0.68 m/s².
b) The force that maintains circular motion is the centripetal force:
Where:
m: is the mass of the car
The mass is given by:
Where P is the weight of the car = 13561 N
Now, the centripetal force is:
Then, the force that maintains circular motion is 940.03 N.
c) Since the centripetal force is equal to the coefficient of static friction, this can be calculated as follows:
Therefore, the minimum coefficient of static friction between the tires and the road is 0.069.
I hope it helps you!
