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Galina-37 [17]
3 years ago
7

Simply 7p2 x 3p 14p4

Mathematics
1 answer:
vivado [14]3 years ago
6 0

Answer:

{ \tt{ =  \frac{7 {p}^{2}  \times 3p}{14 {p}^{4} } }} \\  = { \tt{ \frac{21 {p}^{3} }{14 {p}^{4} } }} \\  = { \tt{1.5 {p}^{ - 1} }}

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Answer:

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Y=x^2 -9x at x = 4 Find an equation of the tangent an an equation of the normal
Montano1993 [528]

The tangent line to <em>y</em> = <em>f(x)</em> at a point (<em>a</em>, <em>f(a)</em> ) has slope d<em>y</em>/d<em>x</em> at <em>x</em> = <em>a</em>. So first compute the derivative:

<em>y</em> = <em>x</em>² - 9<em>x</em>   →   d<em>y</em>/d<em>x</em> = 2<em>x</em> - 9

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Then use the point-slope formula to get the equation of the tangent line:

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The normal line is perpendicular to the tangent, so its slope is -1/(-1) = 1. It passes through the same point, so its equation is

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In the figure below, segment AC is congruent to segment AB:
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