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Dahasolnce [82]
3 years ago
5

A door with width 4.20m has an arc as shown in the diagram. Find: a) the radius of the arc, to the nearest cm. b) the length of

the arc, to the nearest cm

Mathematics
2 answers:
Ksju [112]3 years ago
5 0

Hi there!

~

R = \frac{2.1}{sin 67.5}

Arc = R \frac{3\pi }{4}

(A)

Hope this helped you!

lions [1.4K]3 years ago
5 0

Answer:

a. 2m

b. 5m

Step-by-step explanation:

a. from the triangle assuming ABC

half triangle ABC will be ABO and ACO

AO = OB = 4.20m ÷ 2

AO = OB = 2.1m

finding the angle between AB and AC

360 - 225 = 135°

the angle between AB and AO

135÷2= 67.5°

using sin to find the length of AB = radius

sin 67.5 = 2.1/r

r= 2.2730 ~2m

b. theta/360 ×2πr = length of the arc

L= 135/360×2×22/7 × 2.2730

Length of the arc = 5.3578m ~ 5m

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