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Dahasolnce [82]
2 years ago
5

A door with width 4.20m has an arc as shown in the diagram. Find: a) the radius of the arc, to the nearest cm. b) the length of

the arc, to the nearest cm

Mathematics
2 answers:
Ksju [112]2 years ago
5 0

Hi there!

~

R = \frac{2.1}{sin 67.5}

Arc = R \frac{3\pi }{4}

(A)

Hope this helped you!

lions [1.4K]2 years ago
5 0

Answer:

a. 2m

b. 5m

Step-by-step explanation:

a. from the triangle assuming ABC

half triangle ABC will be ABO and ACO

AO = OB = 4.20m ÷ 2

AO = OB = 2.1m

finding the angle between AB and AC

360 - 225 = 135°

the angle between AB and AO

135÷2= 67.5°

using sin to find the length of AB = radius

sin 67.5 = 2.1/r

r= 2.2730 ~2m

b. theta/360 ×2πr = length of the arc

L= 135/360×2×22/7 × 2.2730

Length of the arc = 5.3578m ~ 5m

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Find the distance and midpoint of a segment with the following endpoints: (5,-1) and (-9,-1)
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Answer:

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General Formulas and Concepts:

  • Order of Operations: BPEMDAS
  • Distance Formula: d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}
  • Midpoint Formula: (\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})

Step-by-step explanation:

<u>Step 1: Define</u>

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(-9, -1)

<u>Step 2: Find distance </u><em><u>d</u></em>

  1. Substitute:                    d = \sqrt{(-9-5)^2+(-1-(-1))^2}
  2. Simplify:                        d = \sqrt{(-9-5)^2+(-1+1)^2}
  3. Subtract/Add:               d = \sqrt{(-14)^2+(0)^2}
  4. Evaluate:                       d = \sqrt{196}
  5. Evaluate:                       d = \14

<u>Step 3: Find Midpoint</u>

  1. Substitute:                    (\frac{5-9}{2},\frac{-1-1}{2})
  2. Subtract:                       (\frac{-4}{2},\frac{-2}{2})
  3. Divide:                          (-2,-1)
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Answer:

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