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Allushta [10]
3 years ago
15

What the concept of electronic transition​

Chemistry
1 answer:
joja [24]3 years ago
4 0

Answer: Electronic transition moments are defined as the probability for a given excitation energy transition to take place. It should be evident that the transition moment depends upon the spin-orbit coupling of the electrons in both the ground and excited states.

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Does the nucleus (protons and neutrons) weigh more than the electrons?
Butoxors [25]
The mass of nucleons (and thus of the nucleus) is roughly 1000 times greater than that of electrons.
3 0
4 years ago
Read 2 more answers
A 72.0 mL aliquot of a 1.40 M solution is diluted to a total volume of 248 mL. A 124 mL portion of that solution is diluted by a
Aliun [14]

Answer: 0.20 M

Explanation:

According to the dilution law,

M_1V_1=M_2V_2

where,

M_1 = molarity of stock solution = 1.40 M

V_1 = volume of stock solution = 72.0 ml

M_2 = molarity of diluted solution = m

V_2 = volume of diluted solution = 248 ml

1.40\times 72.0=m\times 248

m=0.41M

Now 124 mL portion of this prepared solution is diluted by adding 133 mL of water.

According to the dilution law,

M_1V_1=M_2V_2

where,

M_1 = molarity of stock solution = 0.41 M

V_1 = volume of stock solution = 124 ml

M_2 = molarity of diluted solution = m

V_2 = volume of diluted solution = (124 +133) ml = 257 ml

0.41\times 124=m\times 257

m=0.20M

Thus the final concentration of the solution is 0.20 M.

8 0
4 years ago
Calculate the new volume of 1.23 mL of a gas at 32 C is subjected to drop in temperature of 20 degrees Celsius
kotykmax [81]

Answer:

1,15mL = V₂

Explanation:

Based on Charle's law the volume is directely proportional to the absolute temperature in a gas under constant pressure. The equation is:

V₁T₂ = V₂T₁

<em>Where V is volume and T absolute temperature of a gas where 1 is initial state and 2, final state.</em>

The V₁ is 1.23mL

T₁ = 32°C + 273.15 = 305.15K

T₂ = T₁ - 20°C = 285.15K

Replacing:

1.23mL*285.15K = V₂*305.15K

<h3>1,15mL = V₂</h3>

<em />

8 0
3 years ago
Wine goes bad soon after opening because the ethanol (CH,CH,OH) in it reacts with oxygen gas (0.) from the air to form water (11
daser333 [38]

<u>Answer:</u> The mass of water produced is 1.8 grams

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

Given mass of ethanol = 4.59 g

Molar mass of ethanol = 46.07 g/mol

Putting values in equation 1, we get:

\text{Moles of ethanol}=\frac{4.59g}{46.07g/mol}=0.0996mol

The chemical equation for the reaction of ethanol with oxygen gas follows:

CH_3CH_2OH+O_2\rightarrow CH_3COOH+H_2O

By Stoichiometry of the reaction;

1 mole of ethanol produces 1 mole of water.

So, 0.0996 moles of ethanol will produce = \frac{1}{1}\times 0.0996=0.0996mol of water.

Now, calculating the mass of water from equation 1, we get:

Molar mass of water = 18 g/mol

Moles of water = 0.0996 moles

Putting values in equation 1, we get:

0.0996mol=\frac{\text{Mass of water}}{18g/mol}\\\\\text{Mass of water}=(0.0996mol\times 18g/mol)=1.8g

Hence, the mass of water produced is 1.8 grams

5 0
3 years ago
Briefly discuss interpretations of your observations and results. Include in your discussion, any conclusions drawn from the res
VMariaS [17]

Answer:

In comparison to Part 1 of this experiment, we observed similar reactions when determining the make up of our unknown. When testing for Mn2+ we observed a color change that resulted in a darker brown/red color, when testing for Co2+ we observed the formation of foamy bubbles but we could not conclude that a gas had formed, when testing for Fe3+ the result was a liquid red in color, when testing for Cr3+ we observed no change, when testing for Zn2+ we observed the formation of a pink/red liquid, when testing for K+ we observed the formation of a precipitate, when testing for Ca2+ we observe the formation of a precipitate. Sources of error may have occurred when observing whether or not an actual reaction had taken place or not, using glassware that wasn't fully cleaned, or the accidental mix of various other liquids in the lab

Explanation:

4 0
4 years ago
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