Answer:
ΔT = Tfinal − Tinitial = 150°C − 35.0°C = 125°C
given the specific heat of iron as 0.108 cal/g·°C
heat=(100.0 g)(0.108 cal /g· °C )(125°C) =
100x 0.108x125= 1350 cal
<span>solution of KI becomes saturated at 10 degrees when around 135-138g KI are added to 100 g of water, so it should be still unsaturated, A. unsaturated (although it is very close to saturation)</span>
Answer:
a) 2NaOH+H2SO4→Na2SO4+2H2O2NaOH+H2SO4→Na2SO4+2H2O
b) Số phân tử NaOH : Số phân tử H2SO4 = 2:1
Số phân tử NaOH : Số phân tử Na2SO4 = 2:1
Số phân tử NaOH : Số phân tử H2O = 2:2
Explanation:
Conditions:
Low pressure and low temperature
Low pressure and high temperature
High pressure and low temperature
High pressure and high temperature
Answer:
find the number of moles of solute dissolved in solution
,
find the volume of solution in liters,
then divide moles solute by liters solution
Explanation:
