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mario62 [17]
3 years ago
12

an aqueous solution contains 1.2mM of total ions. if the solution is NaCl (aq), what is the concentration of chloride ions?

Chemistry
1 answer:
Genrish500 [490]3 years ago
5 0

Explanation:

As the total concentration is given as 1.2 mM. And, it is also given that salt present in the solution is NaCl.

As sodium chloride is an ionic compound so, when it is added to water then it will dissociate into sodium and chlorine ions as follows.

           NaCl \rightarrow Na^{+} + Cl^{-}

So, it means in total there will be formation of 2 ions when one molecules of NaCl dissociates.

Therefore, concentration of chlorine ions will be calculated as follows.

       Concentration of Cl^{-} ions = \frac{1.2mM}{2}

                                                        = 0.6 mM

Thus, we can conclude that the concentration of chloride ions is 0.6 mM.

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What is the pOH of a<br> 5.6 x 10-5 M solution of cesium<br> hydroxide (CsOH)?
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Answer: 4.25

Explanation: CsOH=Cs+

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7 0
3 years ago
Please and thank you
Virty [35]

3.8mL of 0.42 phosphoric acid is required.

Reaction

2H3PO4 + 3CaCL3 → Ca3(PO)4 + 6HCl

moles CaCl2 =0.16 mol/L x0.010 L = 0.0016 mol

moles of H3Po4

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= 0.00106 mol

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brainly.com/question/23276655

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4 0
2 years ago
I set up the conversion factor as 1 mol H20 / 18.02 g H2O because?
Andrej [43]

Answer:

How many grams of H2O are in 1.0 mole of H2O?

18.02 grams

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#Yourchuu

8 0
3 years ago
What is the mass of a sample of iron if that sample lost 2300J of heat energy when it cooled from 80 oC to 30°C? The specific he
irakobra [83]
102 grams.
Equation:
Quantify of heat = mass x specific heat x difference in temperature
We have: quantity of heat : 2300J
specific heat: .449 J/g
difference in t: 80 - 30 = 50
Solve for mass: 2300 = mass x 0.449 x 50
mass = 102.449
2 sig-figs --> 102 grams
7 0
3 years ago
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