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3 years ago

28a-4a^2 Helpp it’s simplifying

Mathematics

1 answer:

olga nikolaevna [1]3 years ago

4 0

Answer:

${ \tt{ = 28a - {4a}^{2} }} \\ = 4a(7 - a)$

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A metal soup can is 4 in. tall and has a diameter of 6 in.

sukhopar [10]

The amount of metal used to make the can = surface area of cylindrical can, which is: D. 42π in².

<h3>What is the Surface Area of a Cylinder?</h3>

A can is a cylinder.

Surface area of a cylinder = 2πrh + 2πr²

Thus:

Amount of metal used to make the can = surface area of the can

r = 6/2 = 3 in.

h = 4 in.

Therefore:

Surface area = 2×π×3×4 + 2×π×3²

Surface area = 24π + 18π

Surface area = 42π in².

Learn more about the surface area of a cylinder on:

brainly.com/question/14657844

4 0

2 years ago

Fill in the table using this function rule.

Elodia [21]

Answer:

1) 16
2) 12
4) 4
5) 0

Step-by-step explanation:

Plug in the value for x in the equation above and solve for y for all 5.

3 0

2 years ago

Five times the sum of a number and 27 is greater than or equal to six times the sum of that number and 26. What's

lakkis [162]

Answer:

$x \leqslant - 21$

Step-by-step explanation:

$5(x + 27) \geqslant 6(x + 26)$ $5x + 135 \geqslant 6x + 156$

$- 21 \geqslant x$

$x \leqslant - 21$

5 0

2 years ago

If 10^x equals 0.1 percent of 10^y, where x and y are integers, which of the following must be true?

andrew-mc [135]

$10^x=0.1 \% \times 10^y \\ \\
10^x=\frac{0.1}{100} \times 10^y \\ \\
10^x=\frac{1}{1000} \times 10^y \\ \\
10^x=\frac{10^y}{10^3} \\ \\
10^x=10^{y-3} \\ \\
\log_{10} 10^x=\log_{10} 10^{y-3} \\ \\
x=y-3 \\ \\
y=x+3$

The answer is B.

5 0

3 years ago

The compressive strength of concrete is normally distributed with mu = 2500 psi and sigma = 50 psi. A random sample of n = 8 spe

Nata [24]

Answer:

$X \sim N(2500,50)$

Where $\mu=2500$ and $\sigma=50$

We select a sample size of n =8. Since the distribution for X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$SE = \frac{50}{\sqrt{8}}= 17.678 psi$

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

Solution to the problem

Let X the random variable that represent the compressive strength of concrete of a population, and for this case we know the distribution for X is given by:

$X \sim N(2500,50)$

Where $\mu=2500$ and $\sigma=50$

We select a sample size of n =8. Since the distribution for X is normal then we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

And the standard error would be:

$SE = \frac{50}{\sqrt{8}}= 17.678 psi$

7 0

3 years ago