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3 years ago

._. Help me please I’m putting my faith in this app.

Mathematics

1 answer:

IRINA_888 [86]3 years ago

8 0

Vas happenin!
Hope your day is going well
I think it’s A
Sorry if it’s wrong
Hope this helps *smiles*

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Step-by-step explanation:

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3 years ago

To find the interquartile range you need to ____the upper and lower quartile values.

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Answer:

The correct options are: Interquartile ranges are not significantly impacted by outliers. Lower and upper quartiles are needed to find the interquartile range. The data values should be listed in order before trying to find the interquartile range. The option Subtract the lowest and highest values to find the interquartile range is incorrect because the difference between lowest and highest values will give us range. The option A small interquartile range means the data is spread far away from the median is incorrect because a small interquartile means data is nor spread far away from the median

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3 years ago

Read 2 more answers

At a school, 177 students play a sport. This is 60% of the students that go to the school. How many students are at the school?

TEA [102]

Answer:

the answer is 205

Step-by-step explanation:

%/100 X is/of 177 IS 60% of the students. so you put 60/100 and multiply 177/X 177X100=17700. Now divide that by 60 and you come up with 28.33. This obviously is not the answer so you add 28 (does not round up to 29) to 177 and you get 205.

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3 years ago

The tee for the sixth hole on a golf course is 305 yards from the tee. On that hole, Marsha hooked her ball to the left, as sket

EleoNora [17]

Answer:

Correct answer is option D. 96.4 yd.

Step-by-step explanation:

Please refer to the attached figure for labeling of the given diagram.

ABC is a triangle with the following labeling:

A is the hole, B is the Tee and C is the point where the ball is.

Sides are labeled as:

$a =255\ yd\\c = 305\ yd\\\angle B =17^\circ$

To find:

Side $b = ?$

Solution:

Here, we have one angle and two sides . Third side of the triangle is to be found opposite to the given angle.

We can use cosine formula here to find the value of the unknown side.

$cos B = \dfrac{a^{2}+c^{2}-b^{2}}{2ac}$

Putting all the values:

$cos 17 = \dfrac{255^{2}+305^{2}-b^{2}}{2\times 255\times 305}\\\Rightarrow 0.956 = \dfrac{65025+93025-b^{2}}{155550}\\\Rightarrow 148753.2= 158050-b^{2}\\\Rightarrow b^{2}= 158050-148753.2\\\Rightarrow b^{2}= 9296.795\\\Rightarrow b= 96.42\ yd$

So, the distance between the Ball and hole is 96.42 yd

Correct answer is option D. 96.4 yd.

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3 years ago