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2 years ago

The production of electricity from fission nuclear reactions in power plants is regulated by controlling

Physics

2 answers:

marin [14]2 years ago

4 0

Answer:

option (D)

Explanation:

It is controlled by the amount of neutrons available.

The rate of fission of heavy element is controlled by the number the number of neutrons. in the fission reaction of Uranium - 235, when one neutron is bombarded on one Uranium 235, three neutrons, small elements along with lot of energy is produced. Now three neutrons bombard three Uranium 235 atoms so that the lot of amount of energy is liberated. it is called uncontrolled chain reaction.

When the number of neutrons are absorbed and only one neutron is available for fission, then energy is in controlled manner and it is called controlled fission reaction. In this reaction, controlled amount of energy is released.

Anna007 [38]2 years ago

3 0

D. or "the amount of neutrons available.

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Air, water and salt solution are given in the table.

Oxana [17]

Answer:

I need help

Explanation:

Albert tries to move a 200 N car and it moves 0 m. A tow truck tries to move the 200 N car and it moves 2 m off the ground onto the truck bed. Who put more work into moving the car? Explain your response using the space below. Be sure to show your calculations. *

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3 years ago

A 1kg cart slams into a stationary 1kg cart at 2 m/s. The carts stick together and move forward at a speed of 1 m/sl. Determine

finlep [7]

Answer:

No, it is not conserved

Explanation:

Let's calculate the total kinetic energy before the collision and compare it with the total kinetic energy after the collision.

The total kinetic energy before the collision is:

$K_i = K_1 + K_2 = \frac{1}{2}mv_1^2 + \frac{1}{2}mv_2^2=\frac{1}{2}(1 kg)(2 m/s)^2+\frac{1}{2}(1 kg)(0)^2=2 J$

where m1 = m2 = 1 kg are the masses of the two carts, v1=2 m/s is the speed of the first cart, and where v2=0 is the speed of the second cart, which is zero because it is stationary.

After the collision, the two carts stick together with same speed v=1 m/s; their total kinetic energy is

$K_f = \frac{1}{2}(m_1+m_2)v^2=\frac{1}{2}(1 kg+1kg)(1 m/s)^2=1 J$

So, we see that the kinetic energy was not conserved, because the initial kinetic energy was 2 J while the final kinetic energy is 1 J. This means that this is an inelastic collision, in which only the total momentum is conserved. This loss of kinetic energy does not violate the law of conservation of energy: in fact, the energy lost has simply been converted into another form of energy, such as heat, during the collision.

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3 years ago

Umar has two copper pans, each containing 500cm3 of water. Pan A has a mass of 750g and pan B has a mass of 1.5kg. Which pan wil

Olin [163]

Answer:

heat required in pan B is more than pan A

Explanation:

Heat required to raise the temperature of the substance is given by the formula

$Q = ms\Delta T$

now we know that both pan contains same volume of water while the mass of pan is different

So here heat required to raise the temperature of water in Pan A is given as

$Q_1 = (m_w s_w + m_ps_p)\delta T$

$Q_1 = (0.5(4186) + 0.750(s))\Delta T$

Now similarly for other pan we have

$Q_2 = (m_w s_w + m_ps_p)\delta T$

$Q_2 = (0.5(4186) + 1.50(s))\Delta T$

So here by comparing the two equations we can say that heat required in pan B is more than pan A

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3 years ago

During science class, Ava and Justin were discussing the rotation of the Sun and debating over which model would best illustrate

agasfer [191]

Answer:

it would b B

Explanation:

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3 years ago

20 kg object travels 28 meter and stops. coefficient friction= 0.085 how much work was done by friction?

Tresset [83]

Assuming it is on a horizontal surface:
friction = μR
R = 20g (g is gravity 9.81)
so Friction = 0.085 x 20g
Work done is force x distance
so Work done = 0.085 x 20g x 28
= 466.956 J

7 0

3 years ago