car starts from rest
final speed attained by the car is
acceleration of the car will be
now the time to reach this final speed will be
so it required 1.39 s to reach this final speed
We will make the comparison between each of the sizes against the known wavelengths.
In the case of the <em>hydrogen atom</em>, we know that this is equivalent to 
m on average, which corresponds to the wavelength corresponding to X-rays.
In the case of the <em>Virus</em> we know that it is oscillating in a size of 30nm to 200 nm, so the size of the virus is equivalent to the range of the wavelength of an ultraviolet ray.
In the case of <em>height</em>, it fluctuates in a person around 
to 
m, which falls to the wavelength of a radio wave.
In a transverse wave:
- Oscillations are perpendicular to the direction of energy travelling
- Frequency is the amount of complete waves passing a certain point in one second (measured in hertz, Hz)
- Wavelength is the distance from any point on one wave to the same point on the following wave
- The amplitude is the maximum displacement of the particles from their average position (and be measured from the horizontal mid-point of the wave to either the peak or trough)
There isn't always a defined relationship between these features. However, frequency × wavelength = velocity of the wave.
Answer:
Explanation:
fringe separation or fringe width is directly proportional to wavelength .
Δ₁ / Δ₂ = wave length of first laser / wavelength of second laser
Δ₁ is fringe separation in first case and Δ₂ is fringe separation in second case.
putting the given values
632.8 / wavelength of second laser = 4.5 / 4.64
wavelength of second laser = 632.8 x (4.64 / 4.5)
= 652.48 nm
652 nm
Answer:
ωB = 300 rad/s
ωC = 600 rad/s
Explanation:
The linear velocity of the belt is the same at pulley A as it is at pulley D.
vA = vD
ωA rA = ωD rD
ωD = (rA / rD) ωA
Pulley B has the same angular velocity as pulley D.
ωB = ωD
The linear velocity of the belt is the same at pulley B as it is at pulley C.
vB = vC
ωB rB = ωC rC
ωC = (rB / rC) ωB
Given:
ω₀A = 40 rad/s
αA = 20 rad/s²
t = 3 s
Find: ωA
ω = αt + ω₀
ωA = (20 rad/s²) (3 s) + 40 rad/s
ωA = 100 rad/s
ωD = (rA / rD) ωA = (75 mm / 25 mm) (100 rad/s) = 300 rad/s
ωB = ωD = 300 rad/s
ωC = (rB / rC) ωB = (100 mm / 50 mm) (300 rad/s) = 600 rad/s
