Answer: ![0.75\ cm](https://tex.z-dn.net/?f=0.75%5C%20cm)
Explanation:
Given
Wavelength of light ![\lambda=500\ nm](https://tex.z-dn.net/?f=%5Clambda%3D500%5C%20nm)
Screen is
away
Distance between two adjacent bright fringe is ![\Delta y=\dfrac{\lambda D}{d}](https://tex.z-dn.net/?f=%5CDelta%20y%3D%5Cdfrac%7B%5Clambda%20D%7D%7Bd%7D)
When same experiment done in water, wavelength reduce to ![\dfrac{\lambda }{\mu}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Clambda%20%7D%7B%5Cmu%7D)
So, the distance between the two adjacent bright fringe is ![\Delta y'=\dfrac{\lambda D}{\mu d}](https://tex.z-dn.net/?f=%5CDelta%20y%27%3D%5Cdfrac%7B%5Clambda%20D%7D%7B%5Cmu%20d%7D)
Keeping other factor same, distance becomes
![\Rightarrow \dfrac{1}{\frac{4}{3}}=\dfrac{3}{4}\quad \text{Refractive index of water is }\dfrac{4}{3}\\\\\Rightarrow 0.75\ cm](https://tex.z-dn.net/?f=%5CRightarrow%20%5Cdfrac%7B1%7D%7B%5Cfrac%7B4%7D%7B3%7D%7D%3D%5Cdfrac%7B3%7D%7B4%7D%5Cquad%20%5Ctext%7BRefractive%20index%20of%20water%20is%20%7D%5Cdfrac%7B4%7D%7B3%7D%5C%5C%5C%5C%5CRightarrow%200.75%5C%20cm)
Answer:
D = 527.31 Km
Explanation:
given,
angle of ship, θ = 23.5° N of W
distance travel in the direction = 575 Km
Distance of ship in west from harbor = ?
now,
Distance of the ship in the west direction
D = d cos θ
d = 575 Km
θ = 23.5°
inserting all the values
D = 575 x cos 23.5°
D = 575 x 0.91706
D = 527.31 Km
Hence, the distance travel by the ship in west from harbor is equal to D = 527.31 Km
The spring constant is 181.0 N/m
Explanation:
We can solve the problem by applying the law of conservation of energy. In fact, the elastic potential energy initially stored in the compressed spring is completely converted into gravitational potential energy of the dart when the dart is at its maximum height. Therefore, we can write:
![\frac{1}{2}kx^2 = mgh](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dkx%5E2%20%3D%20mgh)
where the term on the left represents the elastic potential energy of the spring while the term on the right is the gravitational potential energy of the dart at maximum height, and where
k is the spring constant of the spring
x = 2.08 cm = 0.0208 m is the compression of the spring
m = 12.3 g = 0.00123 kg is the mass of the dart
is the acceleration due to gravity
h = 3.25 m is the maximum height of the dart
Solving for k, we find:
![k=\frac{2mgh}{x^2}=\frac{2(0.00123)(9.8)(3.25)}{(0.0208)^2}=181.0 N/m](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B2mgh%7D%7Bx%5E2%7D%3D%5Cfrac%7B2%280.00123%29%289.8%29%283.25%29%7D%7B%280.0208%29%5E2%7D%3D181.0%20N%2Fm)
Learn more about potential energy:
brainly.com/question/1198647
brainly.com/question/10770261
#LearnwithBrainly
Answer:
C. Both A and B
Explanation:
<em>Electronic leveling systems: </em>These are automatic lifting jacks use for raising wheels and vehicle when parked or when work is to be done on the vehicle engine underneath or on wheels. unlike the manual jacks it is very quick and efficient.
Both technician right, for Technician A, a weight may be use during the procedure for balancing and leveling when raising, and for Technician B, the sensor in the electronic leveling systems is adjustable to adjust the height so as to maintain balancing and levelling.
Answer:
Seriously I have no idea. I need help with my homework.
Explanation:
I really need help with my homework. Sorry