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gizmo_the_mogwai [7]
4 years ago
15

Help! What will cause an increase in the weight of an object

Chemistry
1 answer:
Vitek1552 [10]4 years ago
7 0
The objects mass I took physical science
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What is the molarity of a 10 L solution containing 5.0 moles of solute?
Setler79 [48]
Molarity = Moles of solute/ L(liters) of solution

So let's plug in the information. 

5.0 moles/10L = 0.5 M


3 0
3 years ago
Read 2 more answers
Please help !!
ipn [44]

<u>Answer:</u>

<u>For 2:</u> The % yield of the product is 92.34 %

<u>For 3:</u> 12.208 L of carbon dioxide will be formed.

<u>Explanation:</u>

  • <u>For 2:</u>

The percent yield of a reaction is calculated by using an equation:

\% \text{yield}=\frac{\text{Actual value}}{\text{Theoretical value}}\times 100              ......(1)

Given values:

Actual value of the product = 78.4 g

Theoretical value of the product = 84.9 g

Plugging values in equation 1:

\% \text{yield}=\frac{78.4 g}{84.9g}\times 100\\\\\% \text{yield}=92.34\%

Hence, the % yield of the product is 92.34 %

  • <u>For 3:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(2)

Given mass of carbon dioxide = 24 g

Molar mass of carbon dioxide = 44 g/mol

Plugging values in equation 1:

\text{Moles of carbon dioxide}=\frac{24g}{44g/mol}=0.545 mol

<u>At STP conditions:</u>

1 mole of a gas occupies 22.4 L of volume

So, 0.545 moles of carbon dioxide will occupy = \frac{22.4L}{1mol}\times 0.545mol=12.208L of volume

Hence, 12.208 L of carbon dioxide will be formed.

5 0
3 years ago
For which applications would you choose a liquid over a gas or solid?
DedPeter [7]

Answer:

Washing Clothes & Dissolving Sugar

Explanation:

Think about each application:

1) Washing clothes: You kind of need water to do this, or not much washing can be done.

2) Linking brake pedals to the brake pads: You don't need any liquids for this. You need solids.

3) Deodorizing a room: You would problem choose an aerosol, which is sprayed, thus a gas.

4) Carving a sculpture: You would use solid tool and a sold sculpture.

5) Dissolving sugar: You need a liquid to dissolve sugar!

6) Painting a wall: Perhaps, you COULD say that the paint is a liquid... but I'm not sure if that really counts. I believe this application would still be solids.

7) A gear for a machine is a solid!

5 0
3 years ago
Read 2 more answers
For some hypothetical metal, the equilibrium number of vacancies at 600°C is 1 × 1025 m-3. If the density and atomic weight of t
makvit [3.9K]

Answer:

\frac{N_{v}}{N}=1.92*10^{-4}

Explanation:

First of all we need to find the amount of atoms per volume (m³). We can do this using the density and the molar mass.

7.40 \frac{g}{cm^{3}}*\frac{1mol}{85.5 g}*\frac{6.023*10^{23}atoms}{1mol}*\frac{1000000 cm^{3}}{1m^{3}}=5.21*10^{28}\frac{atoms}{m^{3}}

Now, the fraction of vacancies is equal to the N(v)/N ratio.

  • N(v) is the number of vacancies 1*10^{25}m^{-3}
  • N is the number of atoms per volume calculated above.

Therefore:  

The fraction of vacancies at 600 °C will be:

\frac{N_{v}}{N}=\frac{1*10^{25}}{5.21*10^{28}}  

\frac{N_{v}}{N}=1.92*10^{-4}

I hope it helps you!

 

7 0
3 years ago
Why is it important to heat analytical reagents and store them in a dessicated atmosphere before use?
schepotkina [342]

Explanation:

In normal atmosphere, analytical reagents may absorb water molecules that may affect the results of chemical reactions. So, in order to get accurate results from these analytical regents, they must be stored in a dessicated atmosphere or heated before being used so that the water molecules must dry away.

5 0
3 years ago
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