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horsena [70]
3 years ago
5

Ford used to make a 7.0 liter engine. Calculate how many many cubic inches would be the same size engine.

Physics
1 answer:
Anestetic [448]3 years ago
3 0

Answer : The volume of engine in cubic inches is, 427.166\text{ inch}^3

Explanation :

As we are given that the volume of engine is, 7.0 liters. Now we have to calculate the volume of engine in cubic inches.

Conversion used :

1\text{ liter}=1000cm^3

So, 7\text{ liter}=7000cm^3

1\text{ inch}=2.54cm

or,

1cm=\frac{1}{2.54}\text{ inch}

1cm^3=(\frac{1}{2.54}\text{ inch})^3

As,

1cm^3=(\frac{1}{2.54}\text{ inch})^3

So,

7000cm^3=\frac{7000cm^3}{1cm^3}\times (\frac{1}{2.54}\text{ inch})^3=427.166\text{ inch}^3

Thu, the volume of engine in cubic inches is, 427.166\text{ inch}^3

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3 years ago
A train at a constant 79.0 km/h moves east for 27.0 min, then in a direction 50.0° east of due north for 29.0 min, and then west
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Answer:

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\theta' = 56.85^{\circ}

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Angle, \theta = 50^{\circ}

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\vec{s'} = 29.25\hat{i} + 24.54\hat{j} km

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\vec{s''} = - vt''hat{i} = - 79\frac{37}{60} = - 48.72\hat{i} km

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\vec{s_{net}} = \vec{s} + \vec{s'} + \vec{s''}

\vec{s_{net}} = 35.5\hat{i} + 29.25\hat{i} + 24.54\hat{j} - 48.72\hat{i}

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v_{avg} = \frac{total displacement, \vec{s_{net}}}{total time, t}

v_{avg} = \frac{16.03\hat{i} + 24.54\hat{j}}{\frac{27 + 29 + 37}{60}}

v_{avg} = 10.34\hat{i} + 15.83\hat{j}) km/h

Magnitude of avg velocity is given by:

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(b) angle can be calculated as:

tan\theta' = \frac{15.83}{10.34}

\theta' = tan^{- 1}\frac{15.83}{10.34} = 56.85^{\circ}

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