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Zarrin [17]
3 years ago
15

I need help with this math problem!!

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
4 0

Answer:C

Step-by-step explanation:

I had the same question

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Consider the inequality x + 7 < 9. Select all the true statements.​
alex41 [277]

Answer:

Step-by-step explanation:

here you go mate

step 1

x + 7 < 9  equation

step 2

x + 7 < 9  subtract -7

x+7(-7)<9(-7)

answer

x<2

3 0
3 years ago
The circumference of a circle is 12 pi what is the diameter​
Zolol [24]

Answer:

Step-by-step explanation:

Givens

C = 12 * pi

C = 2*pi * r

Solution

2*pi * r = 12*pi                        Divide both sides by 2pi

2*pi * r/ 2*pi = 12*pi/2pi

r = 6

Answer: the diameter = 2 * r

the diameter = 12

5 0
3 years ago
Subtract (x^2+3x-4) -(4x-2x^2-3)
Feliz [49]

Answer:

3 x^2 - x + -1

Step-by-step explanation:

Simplify the following:

-(4 x - 2 x^2 - 3) + x^2 + 3 x - 4

Factor -1 out of -2 x^2 + 4 x - 3:

--(2 x^2 - 4 x + 3) + x^2 + 3 x - 4

(-1)^2 = 1:

2 x^2 - 4 x + 3 + x^2 + 3 x - 4

Grouping like terms, 2 x^2 + x^2 + 3 x - 4 x - 4 + 3 = (x^2 + 2 x^2) + (3 x - 4 x) + (-4 + 3):

(x^2 + 2 x^2) + (3 x - 4 x) + (-4 + 3)

x^2 + 2 x^2 = 3 x^2:

3 x^2 + (3 x - 4 x) + (-4 + 3)

3 x - 4 x = -x:

3 x^2 + -x + (-4 + 3)

3 - 4 = -1:

Answer: 3 x^2 - x + -1

4 0
3 years ago
An item is regularly priced at $83. It is now priced at a discount of 55% off the regular price.
mart [117]

Answer:

$45.65 total

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Which lengh can be rounded up to the nearest tenth of an inch a. 66.61 b. 5.055 c.4.91 or d. 6.5
Nesterboy [21]
<span>In the given choices, everything can be rounded into nearest tenths.
a. 66.61 – It can be rounded into 66.6
b. 5.055 – it can be rounded into 5.1
c. 4.91 – it can be rounded into 4.9
d. 6.5 – it stays as is.
So everything can be rounded into nearest tenths, however, Letter b. 5.055 is the only one who were rounded up because the number next to tenths value is 5, so the rules of rounding must be followed

</span>



8 0
3 years ago
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