Answer:
1234285.7 m or 1234.3 km
Explanation:
Let the distance be
, the time taken by P waves be
and the time taken by the S waves be
.


For the P waves,


For the S waves,


Equating the
,

Divide both sides of the equation by 500 to reduce the terms.

Since S waves arrive 2 minutes (= 120 seconds) after P waves,


Substitute this in the equation of the distance.




Substitute this in the equation for
involving
.



It is a reflecting telescope and a compound microscope. I know this for sure
Answer:
Explanation:
we can look for the final velocity of the object using the eqaution of motion as shown:
v² = u²+2gH
v is the final velocity
u is the initial velocity = 10m/s
g is the acceleration due to gravity = 9.81m/s²
H is the height of the object = 175m
Subxtitute the given parameters inti the formula and get v:
v² = 10²+2(9.81)(175)
v² = 100+3433.5
v² = 3533.5
v = √3533.5
v = 59.44m/s
Hence the final velocity of the object is 59.44m/s
The three most normal units of estimation for temperature are Celsius, Fahrenheit, and Kelvin.
A thermometer is an instrument that measures temperature. It can gauge the temperature of a strong, for example, food, fluid like water, or gas like air.
The Celsius scale is important for the decimal measuring standard. The decimal standard of estimation additionally incorporates units of mass, like kilograms, and units of length, like kilometers. Most logical fields measure temperature utilizing the Celsius scale. Zero degrees Celsius is the edge of freezing over water, and 100 degrees Celsius is the limit of water. Three countries don't utilize the Celsius scale. The United States, Burma, and Liberia utilize the Fahrenheit scale to quantify temperature. In any case, even in these nations, researchers utilize the Celsius or kelvin scale to gauge temperature. Water freezes at 32 degrees Fahrenheit and bubbles at 212 degrees Fahrenheit. The Kelvin scale is utilized by physicists and different researchers who need to record exceptionally exact temperatures. The Kelvin scale is the main unit of estimation to incorporate the temperature for "outright zero," the complete shortfall of any intensity energy.
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