Answer:
Part a)
![v = 4.60 m/s](https://tex.z-dn.net/?f=v%20%3D%204.60%20m%2Fs)
Part b)
![v_{1f} = 5.24 m/s](https://tex.z-dn.net/?f=v_%7B1f%7D%20%3D%205.24%20m%2Fs)
Part c)
![v = 3.3 m/s](https://tex.z-dn.net/?f=v%20%3D%203.3%20m%2Fs)
Explanation:
Part a)
Object is thrown sideways
since the railroad car is moving on the track so there is no change in the momentum in the direction of motion of the car
so final speed of the car will not change
![v = 4.60 m/s](https://tex.z-dn.net/?f=v%20%3D%204.60%20m%2Fs)
Part b)
By momentum conservation we can write
![m_1v_{1i} = m_1v_{1f} + m_2v_{2f}](https://tex.z-dn.net/?f=m_1v_%7B1i%7D%20%3D%20m_1v_%7B1f%7D%20%2B%20m_2v_%7B2f%7D)
![150(4.60) = 150 v_{1f} - 21(4.60)](https://tex.z-dn.net/?f=150%284.60%29%20%3D%20150%20v_%7B1f%7D%20-%2021%284.60%29)
![v_{1f} = 5.24 m/s](https://tex.z-dn.net/?f=v_%7B1f%7D%20%3D%205.24%20m%2Fs)
Part c)
Again by momentum conservation we have
![m_1v_{1i} + m_2v_{2i} = (m_1 + m_2)v_f](https://tex.z-dn.net/?f=m_1v_%7B1i%7D%20%2B%20m_2v_%7B2i%7D%20%3D%20%28m_1%20%2B%20m_2%29v_f)
![150(4.60) - 21(6.00) = (150 + 21) v](https://tex.z-dn.net/?f=150%284.60%29%20-%2021%286.00%29%20%3D%20%28150%20%2B%2021%29%20v)
![v = 3.3 m/s](https://tex.z-dn.net/?f=v%20%3D%203.3%20m%2Fs)
Volume=length x breadth x height. It unit is M3
Answer:
Don't you worry, 'cause everything's gonna be alright, ai-a'ight
Be alright, ai-a'ight
Explanation: