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Alekssandra [29.7K]
3 years ago
6

The faintest sound an ear can hear (20 micro-pascals) is roughly ______ times smaller than atmospheric pressure at sea level.

Physics
1 answer:
gtnhenbr [62]3 years ago
6 0

Answer: 5.06\times10^{9}

At sea level, there is one standard atmospheric pressure which is equal to 101.325 kilopascals.

The pressure of faintest sound that a human ear can hear is 20 micro-pascals.

taking the ratio of two:

\frac {101.325 kilopascals. }{20 micropascals} = \frac {101.325 \times 10^{3}Pa}{20 \times 10^{-6}Pa}

=5.06\times10^{9}

Hence, the atmospheric pressure at sea level is 5.06\times10^{9} times greater than the faintest sound that a human ear can hear.



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3 years ago
Steel train rails are laid in 12.0-m-long segments placed end to end. The rails are laid on a winter day when their temperature
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Answer:

a) Space = 6.05 x 10^{-3} m = 0.605 cm

b) Stress= -100.8 x 10^{6} Pa

Explanation:

<em>1) Data Given</em>

L = 12 m , T_i = -9 C \degree, T_f = 33 C \degree

<em>2) Calculate the space using Linear thermal expansion formula</em>

We need to use Linear thermal expansion formula since the space created would be a change on 1 dimension, the increase of the temperature will increase the length of the steel.  The formula is given by:

\Delta L = L_i \alpha_{steel} \Delta T

We have everything except the \alpha_{steel} , so we look for this on a book and we find that \alpha_{steel} = 1.2 x 10^{-5} C^{-1}, so we can replace.

\Delta L = 12 m (1.2 x 10^{-5} C^{-1}) (33 C \degree -(-9 C \degree)) = 12 m (1.2 x 10^{-5} C^{-1}) 42 C \degree =6.048 x 10^{-3} m = 0.6048cm

<em>3) Calculate the stress of the steel </em>

The Stress is the ratio of applied force F to a cross section area - defined as

\sigma = \frac{F_n}{A}

Since we don't have the force and the Area, we need to look for another way to find the stress.

For this we can use the concept called Young's Modulus, defined as : "the mechanical property that measures the stiffness of a solid material", and the formula for this is given by:

Y =\frac{F L}{A \Delta L} (1)

Solving \frac{F}{A} from the previous formula we have this:

\frac{F}{A}  = (Y  Δ L)/L  (2)

From the <em>Linear thermal expansion formula</em> we can solve like this

\frac{\Delta L}{L} =  α  ΔT  (3)

And replacing equation (3) into equation (2) we have:

\frac{F}{A}  = Y α ΔT (4)

We have that the Young's Modulus for the steel is 20x10^{10} Pa, so replacing into equation (4)

\frac{F}{A} = 20x10^{10} Pa (1.2x10^-5 C^-1) (42C) = 100.8 *10^{6} Pa  

That represent the absolute value for the Stress, the sign on this case would be negative since there is a compression.

3 0
4 years ago
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