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3 years ago

How do waves interact with our senses?

Physics

2 answers:

k0ka [10]3 years ago

5 0

Answer:

well sound waves interact with our ears and light interacts with our vision

Explanation:

yan [13]3 years ago

4 0

Answer:

Hearing employs air or water waves, whereas sight uses the electromagnetic spectrum. The electrical and chemical neural impulses are sent through the human auditory nerve to the brain once the mechanical energy of the sound waveform is converted into neurological stimulation.

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If 40.0 kj of energy are absorbed by .500 kg of water 10 degrees c, what is the final temperature of the water?

anastassius [24]

To solve the problem, we must use the following equation:

$Q=mC_s (T_f -T_i)$

where

Q is the amount of heat energy absorbed by the water

m is the mass of the water

Ti and Tf are the initial and final temperature

Cs is the specific heat capacity of the water

The data we have in this problem are:

Q=40.0 kJ

$C_s =4.186 kJ/kg^{\circ}C$

$T_i=10^{\circ}C$

m=0.500 kg

Substituting the data into the equation and re-arranging it, we find

$T_f = T_i + \frac{Q}{mC_s}=10^{\circ}+\frac{40.0 kJ}{(0.500 kg)(4.186 kJ/kg^{\circ}}=29.1^{\circ}C$

So the final temperature of the water will be 29.1 degrees.

8 0

3 years ago

Is the tropic of cancer north or south of the equator?

Daniel [21]

It’s North of the equator

3 0

3 years ago

Read 2 more answers

The wavelength of red helium-neon laser light in air is 632.8 nm.

e-lub [12.9K]

(a) $4.74\cdot 10^14 Hz$

The frequency of an electromagnetic wave is given by:

$f=\frac{c}{\lambda}$

where

$c=3.0\cdot 10^8 m/s$ is the speed of the wave in a vacuum (speed of light)

$\lambda$ is the wavelength

In this problem, we have laser light with wavelength

$\lambda=632.8 nm=6.33\cdot 10^{-7} m$ . Substituting into the formula, we find its frequency:

$f=\frac{3.0\cdot 10^8 m/s}{6.33\cdot 10^{-7} m}=4.74\cdot 10^14 Hz$

(b) 427.6 nm

The wavelength of an electromagnetic wave in a medium is given by:

$\lambda=\frac{\lambda_0}{n}$

where

$\lambda_0$ is the original wavelength in a vacuum (approximately equal to that in air)

$n$ is the index of refraction of the medium

In this problem, we have

$\lambda_0=632.8 nm$

n = 1.48 (index of refraction of glass)

Substituting into the formula,

$\lambda=\frac{632.8 nm}{1.48}=427.6 nm$

(c) $2.03\cdot 10^8 m/s$

The speed of an electromagnetic wave in a medium is

$v=\frac{c}{n}$

where c is the speed of light in a vacuum and n is the refractive index of the medium.

Since in this problem n=1.48, we find

$v=\frac{3\cdot 10^8 m/s}{1.48}=2.03\cdot 10^8 m/s$

3 0

4 years ago

An astronaut on a space walk floats a little too far away

Lady bird [3.3K]

Answer:

He can throw it away from himself.

Explanation:

Newtons Third Law says that everything has an equal, yet opposite reaction on other objects.

3 0

3 years ago

Read 2 more answers

Imagine an alternative universe where the characteristic decay time of neutrons is 3 min instead of 15 min. All other properties

FrozenT [24]

Answer:

(a) $[Y_{p} ]_{max} = \frac{2f}{1+f}$

(b) $f_{new} = 0.013$ ; $[Y_{p} ]_{max}$ = 0.026

Explanation:

Since the neutron-to-proton ratio at the time of nucleosynthesis is given:

$f = \frac{n_{n} }{n_{p} }$

Therefore:

$n_{n} = f*n_{p}$

Then, to determine the maximum ⁴He fraction if all the available $n_{n}$ neutrons bind to all the protons. Since, there are 2 protons and 2 neutrons in a ⁴He nucleus, it shows that there would be $n_{n}/2$ nuclei of ⁴He.

In addition, a ⁴He nucleus has a mass of $4m_{p}$ , where $m_{p}$ is the mass of one proton. Thus, $n_{n}/2$ nuclei of such nuclei will have a mass of $n_{n}/2$ * $4m_{p}$ .