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2 years ago

How do waves interact with our senses?

Physics

2 answers:

k0ka [10]2 years ago

5 0

Answer:

well sound waves interact with our ears and light interacts with our vision

Explanation:

yan [13]2 years ago

4 0

Answer:

Hearing employs air or water waves, whereas sight uses the electromagnetic spectrum. The electrical and chemical neural impulses are sent through the human auditory nerve to the brain once the mechanical energy of the sound waveform is converted into neurological stimulation.

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Determine the CM of a rod assuming its linear mass density λ (its mass per unit length) varies linearly from λ = λ0 at the left

Dahasolnce [82]

Answer:

$x_c= \dfrac{5}{9}L$

$I=\dfrac {7}{12}\lambda_ 0 L^3$

Explanation:

Here mass density of rod is varying so we have to use the concept of integration to find mass and location of center of mass.

At any distance x from point A mass density

$\lambda =\lambda_0+ \dfrac{2\lambda _o-\lambda _o}{L}x$

$\lambda =\lambda_0+ \dfrac{\lambda _o}{L}x$

Lets take element mass at distance x

dm =λ dx

mass moment of inertia

$dI=\lambda x^2dx$

So total moment of inertia

$I=\int_{0}^{L}\lambda x^2dx$

By putting the values

$I=\int_{0}^{L}\lambda_ ox+ \dfrac{\lambda _o}{L}x^3 dx$

By integrating above we can find that

$I=\dfrac {7}{12}\lambda_ 0 L^3$

Now to find location of center mass

$x_c = \dfrac{\int xdm}{dm}$

$x_c = \dfrac{\int_{0}^{L} \lambda_ 0(1+\dfrac{x}{L})xdx}{\int_{0}^{L} \lambda_0(1+\dfrac{x}{L})}$

Now by integrating the above

$x_c=\dfrac{\dfrac{L^2}{2}+\dfrac{L^3}{3L}}{L+\dfrac{L^2}{2L}}$

$x_c= \dfrac{5}{9}L$

So mass moment of inertia $I=\dfrac {7}{12}\lambda_ 0 L^3$ and location of center of mass $x_c= \dfrac{5}{9}L$

8 0

3 years ago

4-7 Please! This is about scientific experiments.

ladessa [460]

Number 4 is c , number 5 is a , number 6 is d and 7 is a

8 0

3 years ago

An event, a person, a deed, or an object can have a long-lasting or momentary effect. How might you determine if the effect has

Amanda [17]

I found a website called Socratic message me and I will tell you

7 0

3 years ago

Two billiard balls move toward each other on a table. The mass of the number three ball, m1, is 5 g with a velocity of 3 m/s. Th

Stels [109]

This question deals with the law of conservation of momentum, which basically says that the total momentum in a system must stay the same, provided there are no outside forces. Since you were given the mass and velocity of the two objects you can find the momentum (p=mv) of each and then add them together to find the total momentum of the system before they collide. This total momentum must be the same after they collide. Since you have the mass and velocity of one of the objects after the collision you can find the its momentum after. Subtract this from the the system total and you will have the momentum of the other object after the collision. Now that you know the momentum of the other object you can find its velocity using p=mv and its mass from before.

Be careful with the velocities. They are vectors, so direction matters. Typically moving to the right is positive (+) and moving to the left is negative (-). It is not clear from your question which direction the objects are moving before and after the collision.

6 0

3 years ago

Read 2 more answers

300kg of water are lifted 10m vertically in 5s show the work done in 30kj and that power is 6kw . Please help me

Mandarinka [93]

Answer:

6KW

Explanation:

The computation is shown below:

We know that

Work done= m ×g× h

Here

W= 300×10×10

= 30000 J

= 30 KJ

And

Power= Work done ÷time taken

P = 30000 ÷ 5

= 6000W

= 6KW

The above represent the answer

3 0

2 years ago