All categories

3 years ago

Write a speech about bringing back fidget toys because they're banned in school

Physics

1 answer:

12345 [234]3 years ago

7 0

I believe that fidget toys should not be brought back in school, reason being is because fidget spinners were originally made for students with example: Autism . Who actually needed them. Now that people who don't need them are buying them and playing with them in the classroom, it causes a complete distraction and is not being used for its original purpose whatsoever .

You might be interested in

How does an inclined plane change distance and how does it change direction

ElenaW [278]

Objects are known to go down because of a unbalanced force

7 0

2 years ago

On a playground, there is a merry‑go‑round. In order to get it moving, Bonnie applies a force of 31 N31 N . The merry‑go‑round m

nika2105 [10]

Answer:

The magnitude of the torque is 263.5 N.

Explanation:

Given that,

Applied force = 31 N

Distance from the axis = 8.5 m

She applies her force perpendicularly to a line drawn from the axis of rotation

So, The angle is 90°

We need to calculate the torque

Using formula of torque

$\tau=Fd\sin\theta$

Where, F = force

d = distance

Put the value into the formula

$\tau=31\times8.5\sin90$

$\tau= 263.5\ N$

Hence, The magnitude of the torque is 263.5 N.

4 0

2 years ago

An object with a non-zero speed must be _________.

pogonyaev

It would be either A or C if its still moving and not stopping

8 0

3 years ago

Read 2 more answers

In attempting to pass the puck to a teammate, a hockey player gives it an initial speed of 2.8 m/s. However, this speed is inade

erastova [34]

Answer:

3.95979 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

$v^2-u^2=2as\\\Rightarrow as=\frac{v^2-u^2}{2}\\\Rightarrow as=\frac{0^2-2.8^2}{2}\\\Rightarrow as=-3.92$

Here $s=\frac{1}{2}s$

$\\\Rightarrow as=-7.84\ m/s^2$

$v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow u=\sqrt{v^2-2as}\\\Rightarrow u=\sqrt{0^2-2\times -7.84}\\\Rightarrow u=3.95979\ m/s$

Initial velocity of the puck should be 3.95979 m/s

8 0

2 years ago

A painter lifts a 2.8 kg bucket using a rope. if the acceleration of the bucket in 3.1 m/s2, what is the tension in the rope (in

ad-work [718]

Refer to the diagram shown below

Given:
m = 2.8 kg, the mass of the bucket
a =3.1 m/s², the acceleration of the bucket
Therefore
W = 2.8*9.8 = 27.44 N, the weight of the bucket.

Let T = the tension in the rope.

From the free body diagram, the net force accelerating the bucket is
T - W = m*a
That is,
T = W + m*a
= 27.44 + 2.8*3.1 N
= 36.12 N

Answer: d. 36.1 N

7 0

3 years ago

Read 2 more answers