Hope it helps you...
Can some do this plzz
1 answer:
Answer:
Step-by-step explanation:
When you factor each equation, you result in two of the factors canceling out, resulting in .
[Top Equation]
The middle number is 3 and the last number is -28.
Factoring means we want something like
(x+_)(x+_)
Which numbers go in the blanks?
We need two numbers that...
Add together to get 3
Multiply together to get -28
Can you think of the two numbers?
Try -4 and 7:
-4+7 = 3
-4*7 = -28
Fill in the blanks in
(x+_)(x+_)
with -4 and 7 to get...
(x-4)(x+7)
[Bottom Equation]
The middle number is -7 and the last number is 12.
Factoring means we want something like
(x+_)(x+_)
Which numbers go in the blanks?
We need two numbers that...
Add together to get -7
Multiply together to get 12
Can you think of the two numbers?
Try -3 and -4:
-3+-4 = -7
-3*-4 = 12
Fill in the blanks in
(x+_)(x+_)
with -3 and -4 to get...
(x-3)(x-4)
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SOLUTION OF TRIANGLE:
a i) use this formula, a² = b² + c² - 2bc cos A
a² = 8² + 10² - 2(8)(10) cos 60
= 84
a = 9.17 cm
UW = 9.17 cm
ii) use formula no 12 as attached :
sin
to solve this,
( sin 40 / 11 ) x 9.17 = 0.5358511
press shift sin on ur calc & the answer is :
FUNCTION
a) f(x) = x-3
g(x) = x²-1
i) f(6) = 6-3
substitute x with the value given in the bracket into equation
f(6) = 6-3
= 3
ii) to do inverse function use this formula :
u = f(x)
u = x - 3
and then make x as the subject
x = u + 3
after that, just change u to x
f-1(x) = x + 3
iii) f [ g(2) ] = f [ g(-2) ] = 0
g(2) = (2)² - 1 g(-2) = (-2)² - 1
= 4 - 1 = 4 - 1
= 3 = 3
f(3) = 3-3
= 0
a i) use this formula, a² = b² + c² - 2bc cos A
a² = 8² + 10² - 2(8)(10) cos 60
= 84
a = 9.17 cm
UW = 9.17 cm
ii) use formula no 12 as attached :
sin
to solve this,
( sin 40 / 11 ) x 9.17 = 0.5358511
press shift sin on ur calc & the answer is :
FUNCTION
a) f(x) = x-3
g(x) = x²-1
i) f(6) = 6-3
substitute x with the value given in the bracket into equation
f(6) = 6-3
= 3
ii) to do inverse function use this formula :
u = f(x)
u = x - 3
and then make x as the subject
x = u + 3
after that, just change u to x
f-1(x) = x + 3
iii) f [ g(2) ] = f [ g(-2) ] = 0
g(2) = (2)² - 1 g(-2) = (-2)² - 1
= 4 - 1 = 4 - 1
= 3 = 3
f(3) = 3-3
= 0