When you multiply two complex numbers given in polar form, the argument of the product is the sum of the arguments of the factors. Meanwhile, the modulus of the product is the product of the moduli of the factors.
In this case, you'd have
and the modulus would simply be
. Since
we would expect the final product to fall in the first quadrant.
The answer is 13 hope I helped
X= -b over 2a = --6 over 2×1=3
y=3²-6(3)-7=-16
vertex is (3,-16)
axis of symmetry is 3
Given : A inequality is given to us . The inequality is 19 ≥ t + 18 ≥ 11 .
To Find : The correct option between the given ones . To write the compound inequality with integers .
Solution : The given inequality to us is 19 ≥ t + 18 ≥ 11 . Let's simplify them seperately .
⇒ 19 ≥ t + 18 .
⇒ t + 18 ≤ 19 .
⇒ t ≤ 19 - 18 .
⇒ t ≤ 1 = 1 ≥ t . ..................(i)
⇒ t + 18 ≥ 11 .
⇒ t ≥ 11 - 18.
⇒ t ≥ -7 . ....................(ii)
<u>On</u><u> </u><u>combing</u><u> </u><u>(</u><u>i</u><u>)</u><u> </u><u>&</u><u> </u><u>(</u><u>ii</u><u>)</u><u> </u><u>.</u>
This means that t is less than or equal to 1 but greater than or equal to (-7) .
