All categories

3 years ago

Fun fact : were all dumb jk

Chemistry

2 answers:

GenaCL600 [577]3 years ago

6 0

Answer:

haha

Explanation:

Yakvenalex [24]3 years ago

6 0

Answer:

i now i am lma/oooo

Explanation:

You might be interested in

100 POINTS ANSWER FAST

alex41 [277]

I believe the answer is a because 2 times 12 is 24. Hope this helped

8 0

3 years ago

Read 2 more answers

The liquid dispensed from a burette is called ___________.

11Alexandr11 [23.1K]

The liquid that is been dispensed during titration as regards this question is Titrant.

Titration can be regarded as common laboratory method that is been carried out during quantitative chemical analysis.

This analysis helps to know the concentration of an identified analyte.

Burette can be regarded as laboratory apparatus.

It is used in the in measurements of variable amounts of liquid ,this apparatus helps in dispensation of liquid, especially when performing titration.

The specifications is been done base on their volume, or resolution.

The liquid that comes out of this apparatus is regarded as Titrant, and this is gotten during titration process, which is usually carried out during volumetric analysis.

Therefore, burrete is used in volumetric analysis.

Learn more at:

brainly.com/question/2728613?referrer=searchResults

8 0

3 years ago

Read 2 more answers

A chemistry student was asked to calculate the number of moles of iron required to react with 1.20 mol of oxygen to produce iron

Delicious77 [7]

Answer:Write and balance the equation

4Fe + 3O2 -> 2Fe2O3

0.32 mol Fe x 2 mol Fe2O3 / 4 mol Fe =

0.16 mol of Fe2O3

Explanation:

8 0

3 years ago

(b) The conductivity of a 0.01 mol dm–3 solution of a monobasic organic acid in water is 5.07 × 10–2 S m–1. If the molar conduct

Zarrin [17]

Explanation:

The given data is as follows.

$\Lambda^{o}_{m}$ (NaCl) = $1.264 \times 10^{-2}$

$\Lambda^{o}_{m}$ (H-O=C-ONO) = $1.046 \times 10^{-2}$

$\Lambda^{o}_{m}$ (HCl) = $4.261 \times 10^{-2}$

Conductivity of monobasic acid is $5.07 \times 10^{-2} S m^{-1}$

Concentration = 0.01 $mol/dm^{3}$

Therefore, molar conductivity ( $\Lambda_{m}$ ) of monobasic acid is calculated as follows.

$\Lambda_{m} = \frac{conductivity}{concentration}$

= $\frac{5.07 \times 10^{-2} S m^{-1}}{0.01 mol/dm^{3}}$

= $\frac{5.07 \times 10^{-2} S m^{-1}}{0.01 mol \times 10^{3}}$

= $5.07 \times 10^{-3} S m^{2} mol^{-1}$

Also, $\Lambda^{o}_{m}$ = $\Lambda^{o}_{m}_{(HCl)} + \Lambda^{o}_{m}_{(H-O=C-ONO)} - \Lambda^{o}_{m}_{(NaCl)}$

= $4.261 \times 10^{-2} + 1.046 \times 10^{-2} - 1.264 \times 10^{-2}$

= $4.043 \times 10^{-2} S m^{2} mol^{-1}$

Relation between degree of dissociation and molar conductivity is as follows.

$\alpha = \frac{\Lambda_{m}}{\Lambda^{o}_{m}}$

= $\frac{5.07 \times 10^{-2} S m^{-1}}{4.043 \times 10^{-2} S m^{2} mol^{-1}}$

= 0.1254

Whereas relation between acid dissociation constant and degree of dissociation is as follows.

K = $\frac{c \times \alpha^{2}}{1 - \alpha}$

Putting the values into the above formula we get the following.

K = $\frac{c \times \alpha^{2}}{1 - \alpha}$

= $\frac{0.01 \times (0.1254)^{2}}{1 - 0.1254}$

= $0.017973 \times 10^{-2}$

= $1.7973 \times 10^{-4}$

Hence, the acid dissociation constant is $1.7973 \times 10^{-4}$ .

Also, relation between $pK_{a}$ and $K_{a}$ is as follows.

$pK_{a} = -log K_{a}$

= $-log (1.7973 \times 10^{-4})$

= 3.7454

Therefore, value of $pK_{a}$ is 3.7454.

3 0

3 years ago

How are new kinds of matter formed in a chemial change?

shtirl [24]

Because the reactants react with each other and chemically react to produce a different product like with fire when it reacts with the wood it burns and the product left behind is a new different substance from the reactants in this case the product is ash

7 0

3 years ago

Read 2 more answers